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ivolga24 [154]
3 years ago
7

A convex mirror, like the passenger-side rearview mirror on a car, has a focal length of -3.0 m . An object is 6.0 m from the mi

rror.Part A) Use ray tracing to determine the location of its image. How far is the image from the mirror? Input positive value if the image is on the same side from the mirror as an object and negative if the image is on the other side.Part B) Is the image upright or inverted? Is it real or virtual?

Physics
1 answer:
Artist 52 [7]3 years ago
8 0

A) -2.0 m

Look at the ray diagram attached in the picture, where:

p identifies the location of the object

q identifies the location of the image

F identifies the focus of the mirror

Each tick represents 1 m

We have

p = 6.0 m is the distance of the object from the mirror

f = -3.0 m is the focal length

From the ray diagram, we see that q has a distance of 2.0 m from the mirror, and it's on the other side of the mirror compared to the object, so

q = -2.0 m

This can also be verified by using the mirror equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-3.0 m}-\frac{1}{6.0 m}=-\frac{3}{6.0 cm}\\q = \frac{-6.0 cm}{3}=-2.0 cm

B) Upright and virtual

As we see from the picture, the image is upright, since it has same orientation as the object.

Also, we notice that the image is on the other side of the mirror, compared to the object. For a mirror,

- An image is said to be real if it is on the same side of the object

- An image is said to be virtual if it is on the opposite side of the mirror

Therefore, this means that the image is virtual.

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Answer:

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Explanation:

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3 years ago
Why does the chord of an electric heater not glow while the heating element does​
8_murik_8 [283]

Answer:

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4 0
3 years ago
A force of 14 N acts on a 5 kg object for 3 seconds.
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Answer: a) 42Nm b) 8.4m/s

Explanation:

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Since Force = mass × acceleration

F = ma

Acceleration is the rate of change in velocity.

F = m(v-u)/t

Cross multiply

Ft = m(v-u)

Since impulse = Ft

and Ft = m(v-u)... (1)

The object change in velocity (v-u) = Ft/m from eqn 1

Going to the question;

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Given force = 14N and time = 3seconds

Impulse = 14×3

Impulse = 42Nm

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v-u = 14×3/5

Change in velocity = 42/5 = 8.4m/s

3 0
3 years ago
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3 0
3 years ago
How long Tina, a ballerina, in the air when she leaps straight up with a speed of 1.8 m/s?
Tems11 [23]

The acceleration of gravity on or near the surface of the Earth is 9.8 m/s².
Anything acted on only by gravity loses 9.8 m/s of upward speed, or gains
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Leaping straight upward at 1.8 m/s, Tina keeps rising until she runs out of
upward speed.  That happens in (1.8/9.8) = 0.1837 second after the leap.

After that, Finkel's First Law of Motion takes over:
"What goes up must come down."

The dropping part of the leap is symmetrical with the first.  Please don't
make me go through proving it.  Tina hits the floor at the same speed of
1.8 m/s with which she left it, and it takes the same amount of time to drop
from the peak to the floor as it took to rise from the floor to the peak.

So her total time out of contact with the floor is

                     2 x (0.1837 sec)  =  0.367 second  (rounded)

3 0
3 years ago
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