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valentina_108 [34]
2 years ago
13

Technician A says that to depressurize high-pressure components of the electronic brake control (EBC) system, research the proce

dure for depressurizing the accumulator in the service information. Technician B says to remove the ABS fuse from the fuse box and apply the brake firmly at least 40 times when depressurizing the components of the EBC system. Who is correct
Engineering
1 answer:
Naddik [55]2 years ago
7 0

Answer:

Both Technician A and Technician B

Explanation:

Information regarding the depressurization of the of the electronic brake control (EBC) is contained in the service manual. Information regarding the depressurization of the accumulator should be researched and information based on the manufacturers information should be followed

Other steps required in depressurization are;

The ignition is placed in the off position

The ABS fuse should be removed from the fuse box

Firmly apply the brakes for at least 40 times

The brakes should be applied to verify that there is no power assist remaining. The brakes should be further pumped for an additional 10 times if there is still power assist.

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Briefly discuss if it would be better to operate with pumps in parallel or series and how your answer would change as the steepn
Aleksandr [31]

Answer:

1) In series, the combined head will move from point 1 to point 2 in theory. However, practically speaking, the combined head and flow rate will move along the system curve to point 3.

2) In parallel, the combined head and volume flow will move along the system curve from point 1 to point 3.

Explanation:

1) Pump in series:

When two or more pumps are connected in series, their resulting pump performance curve will be obtained by adding their respective heads at the same flow rate as shown in the first diagram attached.

In the first diagram, we have 3 curves namely:

- system curve

- single pump curve

- 2 pump in series curve

Also, we have points labeled 1, 2 and 3.

- Point 1 represents the point that the system operates with one pump running.

- Point 2 represents the point where the head of two identical pumps connected in series is twice the head of a single pump flowing at the same rate.

- Point 3 is the point where the system is operating when both pumps are running.

Now, since the flowrate is constant, the combined head will move from point 1 to point 2 in theory. However, practically speaking, the combined head and flow rate will move along the system curve to point 3.

2) Pump in parallel:

When two or more pumps are connected in parallel, their resulting pump performance curve will be obtained by adding their respective flow rates at same head as shown in the second diagram attached.

In the second diagram, we have 3 curves namely:

- system curve

- single pump curve

- 2 pump in series curve

Also, we have points labeled 1, 2 and 3

- Point 1 represents the point that the system operates with one pump running.

- Point 2 represents the point where the flow rate of two identical pumps connected in series is twice the flow rate of a single pump.

- Point 3 is the point where the system is operating when both pumps are running.

In this case, the combined head and volume flow will move along the system curve from point 1 to point 3.

5 0
3 years ago
1. A 260 ft (79.25 m) length of size 4 AWG uncoated copper wire operating at a tem-
Murljashka [212]

A 260 ft (79.25m) length of size 4 AWG uncoated copper wire operating at a temperature of 75°c has a resistance of 0.0792 ohm.

Explanation:

From the given data the area of size 4 AWG of the code is 21.2 mm², then K is the Resistivity of the material at 75°c is taken as ( 0.0214 ohm mm²/m ).

To find the resistance of 260 ft (79.25 m) of size 4 AWG,

R= K * L/ A

K = 0.0214 ohm mm²/m

L = 79.25 m

A = 21.2 mm²

R = 0.0214 * \frac{79.25}{21.2}

  = 0.0214 * 3.738

  = 0.0792 ohm.

Thus the resistance of uncoated copper wire is 0.0792 ohm

5 0
3 years ago
Write two scnr.nextInt statements to get input values into birthMonth and birthYear. Then write a statement to output the month,
aalyn [17]

Answer:

import java.util.Scanner;

public class InputExample {

   public static void main(String[] args) {

       Scanner scnr = new Scanner(System.in);

       int birthMonth;

       int birthYear;

       birthMonth = scnr.nextInt();

       birthYear = scnr.nextInt();

       System.out.println(birthMonth+"/"+birthYear);

   }

}

3 0
3 years ago
Identify the Levels of Biological Organization below. Copy and answer each statement. Write
Dafna1 [17]

Answer:

no idea

Explanation:

gvghvvvghhbbgggggggig gjgjg gjgbg gig gg bg GB g GB GB GB GB g GB GB GB of me and I am a diary and crewmate hide if you see a diary or not the other person is a non-electrolyte or no one vent the imposter win a diary or you can get any more confidently than you are in a spectacular place is the most important points to be mo to get skins and crewmate for a few days to be sure it will be the same for me it will take a while for a couple to get the right angle bu the other one is come to the end and then you have birds to get a lot more than a diary of a candle or no other one in a few weeks or no time to do it for me and my friend who has no idea how much time I have been to a new episodes and the best of all the time I am going sleep

3 0
3 years ago
Do you get a better performance using premier gasoline (Octane number 93) for your compact car?
topjm [15]

Answer:

Yes

Explanation:

As we know that octane number resist the engine from knocking.If knocking can prevent that automatically the performance of engine will increases.If octane number is 100 then it means that knocking tendency in the engine is zero.So higher the octane number better will the performance of the engine.

Generally octane number is 87 but for premier gasoline is 92 or 93.

So we can say that if octane number is  93 then car will give better performance

6 0
3 years ago
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