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Solnce55 [7]
4 years ago
15

HELP!!!! ASAP!!!!!!!!!! HOW ARE REACTANTS DIFFERENT FROM THE PRODUCTS ?

Chemistry
2 answers:
raketka [301]4 years ago
7 0
Reactants are what make up the product.
creativ13 [48]4 years ago
6 0
Reactants will be on the left and products will be on the right
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4 points
musickatia [10]
Divide mass by density to determine volume. 115.384 cm^3 (unsure if you need to round.)
7 0
3 years ago
You wish to make 250. mL of 0.20 M KCl from a stock solution of 1.5 M KCl and DI water.
Nitella [24]

The question requires us to use the dilution formula M_iV_i=M_fV_f, where M_i and V_i are the stock concentration and volume respectively, then M_f and V_f are the dilute concentration and volume respectively.

a. C_s_t_o_c_k= 1.5 M KCI, C_d_i_l_u_t_e=0.20M KCl, V_d_i_l_u_t_e=250ml KCl

b.M_iV_i=M_fV_f\\\implies V_i= \frac{M_fV_f}{M_i} = \frac{0.20M \times 250ml}{1.5M} = 33.3\ ml

To prepare the solution 33.3ml of 1.5M KCl is diluted to a total final volume of 250ml.


8 0
4 years ago
Data has been collected to show that at a given wavelength in a 1 cm pathlength cell, Beer's Law for the absorbance of Co2 is li
White raven [17]

Answer : The concentration of a solution with an absorbance of 0.420 is, 0.162 M

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

As per question, at constant path-length there is a direct relation between absorbance and concentration.

\frac{A_1}{A_2}=\frac{C_1}{C_2}

where,

A = absorbance of solution

C = concentration of solution

l = path length

A_1 = initial absorbance = 0.350

A_2 = final absorbance = 0.420

C_1 = initial concentration = 0.135 M

C_2 = final concentration = ?

Now put all the given value in the above relation, we get:

\frac{0.350}{0.420}=\frac{0.135}{C_2}

C_2=0.162M

Thus, the concentration of a solution with an absorbance of 0.420 is, 0.162 M

4 0
3 years ago
What happens to some of the electrons in an atom when the atom is heated
oksano4ka [1.4K]

Answer:

When the electrons in the atom are excited, for example by being heated, the additional energy pushes the electrons to higher energy orbitals. When the electrons fall back down and leave the excited state, energy is re-emitted in the form of a photon

Explanation:

7 0
3 years ago
Which of the following are effective treatments for some musculoskeletal conditions? Select all that apply. PLEASE ANSWER
Dimas [21]

Answer:

1,3, 4

Explanation:

6 0
4 years ago
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