Answer:
1500kg/m^3
Explanation:
Formula:
d=m/v
Given:
m=1.5kg
v=1000cm^3
(The side length of a cube is always equal to the others)
Required:
d=?
Solution:
d=m/v
d=1.5kg/1000cm^3
d=1.5kg/0.001m^3
d=1500kg/m^3
Hope this helps ;) ❤❤❤
Answer:
The answer is 6.25g.
Explanation:
First create your balanced equation. This will give you the stoich ratios needed to answer the question:
2C8H18 + 25O2 → 16CO2 + 18H2O
Remember, we need to work in terms of NUMBERS, but the question gives us MASS. Therefore the next step is to convert the mass of O2 into moles of O2 by dividing by the molar mass:
7.72 g / 16 g/mol = 0.482 mol
Now we can use the stoich ratio from the equation to determine how many moles of H2O are produced:
x mol H2O / 0.482 mol O2 = 18 H2O / 25 O2
x = 0.347 mol H2O
The question wants the mass of water, so convert moles back into mass by multiplying by the molar mass of water:
0.347 mol x 18 g/mol = 6.25g
Answer:
You didn't provide any statements. If it is an option, art is a form of expression. Something created from imagination that expresses the thoughts and emotions of the artist.
The volume of oxygen at STP required would be 252.0 mL.
<h3>Stoichiometic problem</h3>
The equation for the complete combustion of C2H2 is as below:
![2C_2H_2 + 5O_2 --- > 4CO_2 + 2H_2O](https://tex.z-dn.net/?f=2C_2H_2%20%2B%205O_2%20---%20%3E%204CO_2%20%2B%202H_2O)
The mole ratio of C2H2 to O2 is 2:5.
1 mole of a gas at STP is 22.4 L.
At STP, 100.50 mL of C2H2 will be:
100.50 x 1/22400 = 0.0045 mole
Equivalent mole of O2 according to the balanced equation = 5/2 x 0.0045 = 0.01125 moles
0.01125 moles of O2 at STP = 0.01125 x 22400 = 252.0 mL
Thus, 252.0 mL of O2 gas will be required at STP.
More on stoichiometric problems can be found here: brainly.com/question/14465605
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Um okay so I'm not 100 percent sure so I asked Google and it said the answer is genes.