As aluminium loses 12 moles of electrons oxygen gain 12 moles of electrons.
Explanation
4Al + 3 O2→ Al2O3
first write the ions of Aluminium and oxygen
that is, Aluminium ion is = Al^3+
oxygen ion is = O^2-
therefore one atom of Al loses 3 electrons moles while
one atom of O gain 2 electrons moles
from equation above there a total of number of Al atom are 4 =( 1 x4=4) atoms while
Oxygen atoms are 6= ( 3 x2=6) atoms
therefore the total number of Moles of Al lost is = 3 x 4 = 12 moles of electrons
total number of moles of O gained = 2 x6 = 12 moles of electrons
The reaction between the reactants would be:
CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻
Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.
CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I 0.11 0 0
C -x +x +x
E 0.11 - x x x
Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
Since the given information is Kb, let's find Ka in terms of Kb.
Ka = Kw/Kb, where Kw = 10⁻¹⁴
So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]
Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>
Answer:
A
Explanation:
the Molar mass will be smaller as the content of the container is not directly proportional to the temperature of the water bath.
