Both a particle and a wave?
To solve for the number of moles, we simply have to use the Avogadros number which states that there are 6.022 x 10^23 molecules per mole. Therefore:
number of moles = 6.67 X 10^40 chlorine molecules / (6.022 x 10^23 molecules / mole)
number of moles = 1.108 x 10^17 moles
Molar mass of N = 14 g/molMolar mass of O2 = 32 g/molAdding both masses = 46 g/molActual molar mass/ Empirical molar mass = 138.02 / 46 = 3Now multiplying this co effecient with empirical fomula NO2 = 3(NO2) = N3O6So according to above explanation,D) N3O6, is the correct answer.
Answer:
V2 = 600ml
Explanation:
dilution principle formula
M1V1 = M2V2
C1V1 = C2V2
3 X 20 = 0.1 x V2
60 = 0.1 x V2
V2 = 60/0.1
V2 = 600ml
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