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avanturin [10]
4 years ago
5

What kind of air mass comes from the Gulf of Mexico? A. continental tropical B. continental polar C. maritime tropical D. mariti

me polar
Physics
2 answers:
Yakvenalex [24]4 years ago
8 0
A. Hope this helps! (:
Debora [2.8K]4 years ago
7 0
A continental tropical :)hoep it helps
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What two factors could the students change to investigate how to increase and decrease the magnetic force between the paperclip
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3 years ago
What is the magnitude and direction (right or left) of the
Sunny_sXe [5.5K]

Answer: 12 N to the right

Explanation:

If we calculate the net force acting on the box, we will have:

<u>In y-component:</u>

Fy_{net}=F_{n}+F_{g} (1)

Where F_{n}=12 N is the Normal force, directed upwards and F_{g}=-12 N is the weight of the box (gravity force), directed downwards.

Fy_{net}=12 N-12 N (2)

Fy_{net}=0 N (3) Hence the net force in the vertical component is zero

<u>In x-component:</u>

Fx_{net}=F_{left}+F_{right} (4)

Where F_{left}=-3 N and F_{right}= 15 N

Fx_{net}=-3 N + 15 N (5)

Fx_{net}=12 N (6) This is the net force in the horizontal component

Therefore, the total net force acting on the box is 12 N directed to the right

5 0
3 years ago
Two two advantages and hazards of nuclear reaction.
Oksi-84 [34.3K]

Answer:

advantage : 1) produce no polluting gases .

2)doesn't contribute to global warming .

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2)local thermal pollution from east water affects marine life

4 0
4 years ago
how much force would be required to produce 88 j of work when pushing a box 1.1meters at an angle of 10 degrees?
ycow [4]

Answer:81.235N

Explanation:

Work=88J

theta=10°

distance=1.1 meters

work=force x cos(theta) x distance

88=force x cos10 x 1.1 cos10=0.9848

88=force x 0.9848 x 1.1

88=force x 1.08328

Divide both sides by 1.08328

88/1.08328=(force x 1.08328)/1.08328

81.235=force

Force=81.235

5 0
3 years ago
A magnetic field is used to suspend a wire of mass 0.05 kgkg and length 0.16 mm . The wire is carrying a current of 11 AA . What
pochemuha

Answer:

B=0.27840\ T

Explanation:

Given:

mass of the wire, m=0.05\ kg

length of the wire, L=0.16\ m

current in the wire, I=11\ A

Now form the Lorentz force we know that every current carrying wire experiences a magnetic force on it due to the magnetic field components perpendicular to it.

Mathematically given as:

F=I.L\times B

m.g=I.L\times B

here: we nee to balance the gravitational force on the mass.

B= magnetic field

0.05\times 9.8=11\times 0.16\times B

B=0.27840\ T

This magnetic field must be perpendicular to the direction of current in the wire and the these two directional quantities must lie in a plane normal  to the direction of gravity according to the Fleming's left hand rule.

7 0
3 years ago
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