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MatroZZZ [7]
2 years ago
15

A bicyclist covers the first leg of a journey that is d1meters in t1seconds at a speed of v1m/s and the second leg of d2meters i

n t2seconds at a speed of v2m/sIf his average speed is equal to the average of v1 and v2
then which of the following is true?
1. t1=t2
2. t1≠t2
3. d1=d2
4. d1≠d2
Physics
1 answer:
Murljashka [212]2 years ago
4 0

According to motion in straight line  t1≠t2


A biker travels d1 meters in t1 seconds at v1 m/s for the first leg and d2 meters in t2 seconds at v2 m/s for the second leg. It's possible that t1t2 if his average speed is equal to the average of v1 and v2.
An object is said to be in motion if its position in relation to its surroundings changes over time. It is a shift in an object's position over time. The only type of motion that exists is motion in a straight line.


A reference system is constantly used to describe a particle's motion. An arbitrary origin point is used to create a reference system, and a coordinate system is imagined to be connected to it. The reference system for a specific problem is the coordinate system that has been selected for it. For the majority of the problems, we typically select an earth-based coordinate system as the reference system.


To learn more about Motion in straight lines please visit -brainly.com/question/17675825
#SPJ1

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A 16-cm-long straight line connects the center of a turntable to its edge. The turntable rotates counter-clockwise at 45 rpm. A
Bond [772]

Answer:

\mathbf{V_x = 3.25 \ cm/s}

\mathbf{V_y = 1.29\ cm/s}

Explanation:

Given that:

The radius of the table r = 16 cm  = 0.16 m

The angular velocity = 45 rpm

= 45 \times \dfrac{1}{60}(2 \pi)

= 4.71 rad/s

However, the relative velocity of the bug with turntable is:

v = 3.5 cm/s = 0.035 m/s

Thus, the time taken to reach the bug to the end is:

t = \dfrac{r}{v}

t = \dfrac{0.16}{0.035}

t = 4.571s

So the angle made by the radius r  with the horizontal during the time the bug gets to the end is:

\theta = \omega t

\theta = 4.712 \times 4.571

\theta = 21.54^0

Now, the velocity components of the bug with respect to the table is:

V_x = Vcos \theta

V_x = 0.035 \times cos (21.54^0)

V_x = 0.0325 \ m/s

\text {V_x = 3.25 \ cm/s}\mathbf{V_x = 3.25 \ cm/s}

Also, for the vertical component of the velocity V_y

V_y = V sin \theta

V_y = 0.035 \times sin (21.54^0)

V_y = 0.0129\ m/s

\mathbf{V_y = 1.29\ cm/s}

6 0
2 years ago
550 g of water at 105°C is poured into an 855 g aluminum container with an initial temperature of 11°C. The specific heat of alu
nexus9112 [7]

Answer:

54.22 kJ

Explanation:

In this case, we need to calculate the heat. The expression to use is:

Q = m * C * ΔT

Now, with the specific heat of water (4186 J/ kg K), we can calculate the temperature in which this occurs.

So:

Q = 0.550 * 4186 * (105 - T)

Q = 2302.3 (105 - T)

Q = 241,741.5 - 2302.3T

Now with the Aluminium:

Q = 0.855 * 900 * (T - 11)

Q = 769.5T - 8464.5

Now, with both equations, we solve for the final temperature:

769.5T - 8464.5 = 241,741.5 - 2302.3T

(2302.3 + 769.5)T = 241,741.5 + 8464.5

3071.8T = 250,206

T = 81.45 K

This is the temperature which the change occurs. Now, let's determine the amount of heat from water to Al:

Q = 241,741.5 - 2302.3(81.45)

Q = 54,219.17 J or simply 54.22 kJ.

5 0
3 years ago
if the coefficient of linear expansion of a metal is 2.05× 10^-6 k^-1 what will be its new length if 50cm metal went through a t
boyakko [2]

Answer:

L = L0 (1 + c T)   where c is the coefficient and T the change in temperature

L = 50 ( 1 + 2.05E-6 * 50) = 50.0051 cm

7 0
2 years ago
A 32-n force acts on a small mass in the positive x-direction. a 26-n force also acts on it in the negative x-direction. what is
motikmotik

Equilibrium force is the force that will keep the small mass in place, hence no movement must be made. So we know that 32 N of force is acted towards the positive direction so +32 N. Which is counteracted by 26 N force so:

32 N – 26 N = 6 N (positive)

Since positive 6 is left, therefore this must be acted by an equilibrant negative 6 N.

 

Answer:

<span>- 6 N </span>

6 0
2 years ago
You are on a school bus driving north at 20 m/s. You walk toward the back of the bus with a velocity of 6 m/s. What is your velo
Ganezh [65]
I answered the question but it got deleted?? why?
3 0
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