Question

What is the electric potential energy of a charge that experiences a force of 3.6 x 10^-4N when it is 9.8 x 10^-5 from the source of the electric field

Answer 1

The electric potential energy of the charge is equal to the potential at the location of the charge, V, times the charge, q:
$U=qV$
The potential is given by the magnitude of the electric field, E, times the distance, d:
$V=Ed$
So we have
$U=qEd$ (1)
However, the electric field is equal to the electrical force F divided by the charge q:
$E= \frac{F}{q}$
Therefore (1) becomes
$U=Fd$
And if we use the data of the problem, we can calculate the electrical potential energy of the charge:
$U=Fd=(3.6 \cdot 10^{-4}N)(9.8 \cdot 10^{-5} m)=3.53 \cdot 10^{-8} J$