The sound from mosquito is produced when it vibrates its wings at an average rate of 500 vibrations per second. What is the time
1 answer:
As per the the question the sound source is the mosquito.
the mosquito produces the sound with the help of its wings
as per the question the wings vibrate at the rate of 500 vibrations per second.
we have been asked to calculate the time period of vibration.
we know that that time period is the reciprocal of frequency of vibration
hence time period [T]=
=
=
=0.002 second
hence the time period of the vibration of the wings of the mosquito is 0.002 second.
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Answer:B
Explanation:
Given
First motor has three times as much as power as another
Let the power of smaller motor be P
Therefore bigger motor has power 3 P
and we know that energy
Larger motor
Smaller motor
Therefore smaller motor will do same work if it takes three times the time taken by Larger motor
Answer:
a) V = -0.227 mV
b) V = -0.5169 mV
Explanation:
a)
Inside a sphere with a uniformly distributed charge density, electric field is radial and has a magnitude
E = (qr) / (4πε₀R³)
As we know that
V = -
By solving above equation, we get
V = (-qr²) / (8πε₀R³)
When
R = 1.81 cm
r = 1.2 cm
q = +2.80 fC
ε₀ = 8.85 × 10⁻¹²
V = (-2.80 × 10⁻¹⁵ × (1.2 × 10⁻²)²) / (8 × 3.14 × 8.85 × 10⁻¹² × (1.81 × 10⁻²)³)
V = -2.27 × 10⁻⁴ V
V = -0.227 mV
b)
When
r = R
R = 1.81 cm
q = +2.80 fC
ε₀ = 8.85 × 10⁻¹²
V = (-qR²) / (8πε₀R³)
V = (-q) / (8πε₀R)
V = (-2.80 × 10⁻¹⁵) / (8 × 3.14 × 8.85 × 10⁻¹² × (1.81 × 10⁻²))
V = -5.169 × 10⁻⁴ V
V = -0.5169 mV