Answer:
The force of repulsion between the two balls will increase
Explanation:
The electrostatic force between two charged objects is given by
where
k is the Coulomb's constant
q1 and q2 are the charges of the two objects
r is the distance between the centres of the two objects
We see that the magnitude of the force is directly proportional to the charges on the two objects. in this problem, we have two positively charged balls (so, there is a force of repulsion between them, since like charges repel each other and unlike charges attract each other), and the positive charge in one of them is slowly increased: this means that either 
or 
in the formula is increasing, and so the magnitude of the force is increasing.
-- If the frequency of a wave is too high for our eyes to detect it ... but not <u>too too</u> high ... we call it an <em>ultraviolet </em>wave.
-- If the wave's frequency is even higher than that, we call it an <em>X-ray</em> wave.
-- If the wave's frequency is even higher than that, we call it a <em>Gamma Ray </em>wave.
The direction of the magnetic force on the wire is west.
The magnetic force acting on the moving protons acts northward in the horizontal plane. If the thumb is up (current flows vertically up), the wrapped finger will be counterclockwise.
Therefore, the direction of the magnetic field is counterclockwise. Here, the magnetic field is pointing upwards (vertical magnetic field) and the electrons are moving east. Applying Fleming's left-hand rule here, we can see that the direction of force is along the south direction.
As the change in magnetic flux increases upwards, Lenz's law indicates that the induced magnetic field of the induced current must resist and the inside of the loop must be directed downwards. Using the right-hand rule, we can see that a clockwise current is induced.
Learn more about the magnetic fields here: brainly.com/question/7802337
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