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Lunna [17]
3 years ago
14

The sum of 117 and 12 times a number is negative 45. What is the number? | I

Mathematics
1 answer:
MissTica3 years ago
7 0

Answer: - .35 or 13.5 depending on how the equation is written.

Step-by-step explanation:

-45 = (117+12)x

-45 = (129)x

-45/129 = x

roughly = - .35

If that's not it we can do:

-45 = 117+12(x)

-162 = 12x

x = 13.5

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How many real roots does the function
icang [17]

Answer:

Option C is correct i.e. 2.

Step-by-step explanation:

Given the function is f(x) = x² +8x -2.

We can compare it with general quadratic expression i.e. ax² +bx +c.

Then a = 1, b = 8, c = -2.

We can find the number of real root by finding discriminant of the equation ax² +bx +c =0 as follows:-

D = b² -4ac

D = 8² -4*1*-2

D = 64 +8

D = 72.

When D is a positive value, then we have two real roots of the equation.

Hence, option C is correct i.e. 2.

6 0
3 years ago
Help pls...and thank you..
Allisa [31]

Answer:

0 chance because there is no black ones but you would probably pick a yellow one bigger chance for yellow jelly bean.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
When do you need to use two number lines to compare two fractions
OLEGan [10]
Depends on the fraction to determine your answer
4 0
4 years ago
In a certain​ chemical, the ratio of zinc to copper is 3 to 17. A jar of the chemical contains 799 grams of copper. How many gra
dezoksy [38]

Answer:

let's see what to do buddy...

Step-by-step explanation:

\frac{zinc}{copper} =  \frac{3}{17} \\  \\  \frac{zinc}{799} =  \frac{3}{17}

Multiply the sides of the equation by 799

zinc =  \frac{3}{17} \times 799 \\ \\ zinc =  \frac{3}{17} \times 17 \times 47 \\ \\  zinc = 3 \times 47 = 141

So A jar of the chemical contains 141 grams of <em><u>zinc</u></em>.

And we're done.

Thanks for watching buddy good luck.

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8 0
4 years ago
The perimeter of a rectangular field is 60 meters. Its area is 200 square meters. Find its dimensions.
Vanyuwa [196]

Answer:

20 m by 10 m

Step-by-step explanation:

let w be width and l be length , then

2(l + w) = 60 ( divide both sides by 2 )

l + w = 30 ( subtract w from both sides )

l = 30 - w → (1)

lw = 200 → (2)

Substitute l = 30 - w into (2)

w(30 - w) = 200 ← distribute parenthesis on left side

30w - w² = 200 ( subtract 200 from both sides )

30w - w² - 200 = 0 ( multiply through by - 1 )

w² - 30w + 200 = 0 ← in standard form

(w - 10)(w - 20) = 0 ← in factored form

Equate each factor to zero and solve for w

w - 10 = 0 ⇒ w = 10

w - 20 = 0 ⇒ w = 20

Substitute these values into (1)

l = 30 - 10 = 20

l = 30 - 20 = 10

dimensions of field is 20 m by 10 m

4 0
2 years ago
Read 2 more answers
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