Answer:
(a) The electron will move towards the wire.
The direction of the magnetic fields created by the wire can be found via right-hand rule. If you point your thumb towards the direction of the current, and if you curl your fingers, the direction of your four fingers will give the direction of the magnetic field. In this case, magnetic field is around the wire, and into the page just above the wire, where the electron is located.
According to the above formula, the direction of the force the wire applies to the electron can be found by right-hand rule.
Since the electron has a negative charge, the direction of the force is towards the wire.
(b) The proton will veer to the right.
The direction of the magnetic field is the same as the previous part. The proton has a positive charge, and coming from above. The direction of its velocity is downwards. The magnetic field above the wire is pointed into the page. Using the right-hand rule, the magnetic force on the proton is directed to the right, with respect to us.
Answer:
E = 1580594.95 N/C
Explanation:
To find the electric field inside the the non-conducting shell for r=11.2cm you use the Gauss' law:
(1)
dS: differential of the Gaussian surface
Qin: charge inside the Gaussian surface
εo: dielectric permittivity of vacuum = 8.85 × 10-12 C2/N ∙ m2
The electric field is parallel to the dS vector. In this case you have the surface of a sphere, thus you have:
(2)
Qin is calculate by using the charge density:
(3)
Vin is the volume of the spherical shell enclosed by the surface. a is the inner radius.
The charge density is given by:
Next, you use the results of (3), (2) and (1):
Finally, you replace the values of all parameters, and for r = 11.2cm = 0.112m you obtain:
hence, the electric field is 1580594.95 N/C
Answer:
A. It makes astronauts weightless.
Explanation:
Gravity does not make astronauts feel weightless. Astronauts are weightless because they are orbiting at the same rate as their shuttle.
Although the force of gravity weakens as one moves away from the earth surface, it does not mean that this force is absent in orbit
- Gravitational force has a constant acceleration value near the earth surface which is commonly known to be 9.8m/s².
- It is a force of attraction tending to hold and bind bodies together so far they have mass.
- This force keeps every thing from escaping space-ward from the earth surface.
Take the derivative to find the velocity of the object:
The object stops when 
:
so the answer is E.
C option
Power = voltage x current
