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3 years ago

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Find the mass of the solid and the center of mass if the solid region in the first octant is bounded by the coordinate planes an

d the plane . The density of the solid is . x + y + z = 2 (x,y,z) = 4

1 answer:

bazaltina [42]3 years ago

6 0

Answer:Find the attached

Explanation:

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A ball rolls of a cliff and when it lands has a vertical velocity 35 ms ^-1. how high was the cliff?

Licemer1 [7]

Using V²=u² +2gH
let's assume the ball falls from rest, then it's initial velocity = 0ms-¹ (U=0)
then from the above info V= 35ms-¹
g= 10ms-² (value of acceleration due to gravity to the nearest tens)

so input your values above into the given formula to find height
35² = 0² +2×10×H
1225 = 20H
H = 1225÷20 = 61.25m

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4 years ago

A car starts from rest, speeds up with constant acceleration, and travels 400 meters in 10 seconds. What was the acceleration of

PIT_PIT [208]

Answer:

Acceleration of the car will be $a=8m/sec^2$

Explanation:

We have given that car starts from rest so initial velocity of the car u = 0 m/sec

And car traveled 400 m in 10 sec

So distance traveled by car s = 400 m

Time taken to compete this distance t = 10 sec

We have to find the acceleration of the car

From second equation of motion we know that $s=ut+\frac{1}{2}at^2$

So $400=0\times 10+\frac{1}{2}\times a\times 10^2$

$a=8m/sec^2$

So acceleration of the car will be $a=8m/sec^2$

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3 years ago

What is a proper way and a safe way to dispose batteries

gregori [183]

Answer:

throw them away............

4 0

3 years ago

Read 2 more answers

Imagine a universe in which, like in ours, there are two kinds of charges (positive and negative), with the like charges repelli

GuDViN [60]

Answer:

the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

Explanation:

In this hypothetical system the electric force is of type

F = $k' \frac{q_1 q_2 }{r^2}$

in this case the force decays to zero much faster,

if we call Fo the force of Coulomb's law

F₀ = $k \frac{q_1 q_2 }{r^2}$

assuming the constant k is the same

the relationship between the two forces is

F / F₀ = 1 / r

F = F₀ / r

when analyzing this expression the force decays much faster to zero.

In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law

Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

5 0

3 years ago

You are in your car driving on a highway at 23 m/s when you glance in the passenger-side mirror (a convex mirror with radius of

Irina-Kira [14]

Answer:

v = 26. 88 m/s +23 m/s

Explanation:

u = 23 m/s, r = 150 cm, u₁ = 2.0 m/s, s =2.0 m

$\frac{1}{s} +\frac{1}{s'} = \frac{2}{R}$

$\frac{1}{2.0 m} +\frac{1}{s'} = \frac{2}{1.50 m}$

Solve s'

$\frac{1}{s'} = \frac{2}{1.50 m} - \frac{1}{2.0 m}$

$\frac{1}{s'} = 1.833 m$

$s' = - 0.545 m$

To determine the speed of the trick to the highway

$\frac{ds}{dt}= \frac{s^2* \frac{ds}{dt}}{s' ^2} =\frac{2.0 ^2m * 2.0 m/s}{0.545^2m}$

$\frac{ds}{dt} = 26.88 m/s$

Now to determine the velocity highway is going to be

v = ds/dt + u

v = 26. 88 m/s +23 m/s

8 0

3 years ago