A hockey puck moves 28 m southward then 14 m northward and finally 4 m southward Distance? And Magnitude and Direction

Physics

1 answer:

Radda [10]3 years ago

3 0

Explanation:

Given that,

A hockey puck moves 28 m southward then 14 m northward and finally 4 m southward distance.

The total path covered is called distance and the shortest path covered is called displacement.

Distance = 28 m + 14 m + 4 m

Distance = 46 m

Let the nothward direction is positive y axis and southward direction is negative y axis.

Displacement is equal to the difference of final position and the initial position.

Displacement =-28 m - (-4 m)

= -24 m

The magnitude of displacement is in south direction.

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