Answer:
a. NaHCO₃ + HCl → NaCl + H₂O + CO₂
b. 39.14 g is the mass of NaHCO₃ required to produce 20.5 moles of CO₂
Explanation:
A possible reaction for NaHCO₃ to make dioxide is this one, when it reacts with hydrochloric to produce the mentioned gas.
NaHCO₃ + HCl → NaCl + H₂O + CO₂
Ratio in this reaction is 1:1
So 1 mol of baking soda, produce 1 mol of CO₂
Let's calculate the moles
20.5 g CO₂ / 44 g/m = 0.466 moles
This moles of gas came from the same moles of salt.
Molar mass baking soda = 84 g/m
Molar mass . moles = mass
84 g/m . 0.466 moles = 39.14 g
100°C is 273 kelvins.
1°C is 2.73 kelvins.
I guess the closest would be north pole
Answer:
The answer to your question is C₄H₅N₂O
Explanation:
Process
1.- Calculate the percent of oxygen in the sample
Percent of oxygen = 100 - 49.49 - 5.15 - 28.87
Percent of oxygen = 16.49 %
2.- Write the percents as grams
C = 49.49 g
H = 5.15 g
N = 28.87 g
O = 16.47 g
3.- Convert the grams to moles
C 12 g ------------------- 1 mol
49.49 g ---------------- x
x = (49.49 x 1) 12
x = 4.12 moles
H 1 g ------------------- 1 mol
5.15 g ---------------- x
x = (5.15 x 1)/ 1
x = 5.15 moles
N 14 g --------------- 1 mol
28.87 g ---------- x
x = (28.87 x 1) / 14
x = 2 mol
O 16 g ---------------- 1 mol
16.49 g ----------- x
x = (16.49 x 1) / 16
x = 1.03 moles
4.- Divide by the lowest number of moles
C 4.12 / 1.03 = 4
H 5.15 / 1.03 = 5
N 2 / 1.03 = 1.9 ≈ 2
O 1.03 / 1.03 = 1
5.- Write the empirical formula
C₄H₅N₂O
Answer is: 180 <span>grams of 2.5% "h" cream should be mixed.
</span>ω₁ = 2.5% ÷ 100% = 0.025.
ω₂ = 0.25% ÷ 100% = 0.0025.
ω₃ = 1% ÷ 100% = 0.01.
m₂ = 360 g.
m₃ = m₁ + 360 g.
m₁ = ?.
ω₁ · m₁ + ω₂ · m₂ = ω₃ · m₃.
0.025 · m₁ + 0.0025 · 360 g = 0.01 · (m₁ + 360 g).
0.025 · m₁ + 0.9 g = 0.01 · m₁ + 3.6 g.
0.015 · m₁ = 2.7 g.
m₁ = 180 g.
Answer:
I am pretty sure that is a : Catalyst but if i'm not correct sorry
Explanation:
