The number of pulses per second from IGBTs is referred to as

A soil sample has a moist unit weight of 117 pcf, a moisture content of 17 percent, and soil particles with a specific gravity o

nikklg [1K]

Answer:

(A) Dry unit weight. = 15.71 kN/m³ =100.91 pcf

(B) Porosity = 40.82 %

(C) Degree of saturation = 66.52 %

(D) Weight of water, in pounds per cubic foot, to be added to reach full saturation = 81.22 pcf

Explanation:

(A) γd = $\frac{\gamma }{1+w}$ = $\frac{18.379}{1+.17} = 15.71$ KN/m³

(B) $\gamma _d =\frac{G_{s}* \gamma _w }{1+e}$ therefore $1+e = \frac{G_{s}* \gamma _w }{\gamma _d }$ $\frac{2.7*9.81}{15.71} =$ 1.69

Therefore e = 0.69 and

Porososity n = $\frac{e}{1+e}$ = $\frac{0.69}{1+0.69}$ × 100% = 40.82 %

(C) $S_{e} = w*G_{s}$ therefore S = $\frac{w*G_{s}}{e}$ = $\frac{0.17*9.81}{0.69}$ ×100 = 66.52 %

(D) $\gamma _{sat} =\frac{(G_{s}+e) \gamma_{w} }{1+e}$ = $\frac{(2.7+0.69)9.81}{1+0.69}$ = 19.68 kN/m³

The required amount of water is found from γ =ρ×g

ρ mass of water = $\frac{\gamma}{g} = \frac{(19.68-18.38)\frac{kN}{m^{3} } }{9.81 kg\frac{m}{s^{2} } } *\frac{1000 N}{kN} *\frac{9.81 kg\frac{m}{s^{2} } }{N} = 1301 \frac{kg}{m^{3} }$

1 kg/m³ = 0.062 pcf therefore 1301 kg/m³ = 1301 ×0.062 pcf or 81.22 pcf

6 0

3 years ago

From the article "Time Travel Is A Fun Science Fiction Story But Could It Be Real?", Albert Einstein's Theory of Relativity is d

zhannawk [14.2K]

Answer:

Option A

Explanation:

As per the article "Time Travel Is A Fun Science Fiction Story But Could It Be Real?" the gravitational field is a representation of curving space and time. As the gravity becomes strong, the space-time get more curved and hence the time gets slower.

Hence, option A is correct

8 0

3 years ago

Multimeter and the LCD is showing Hz. What's she measuring?

eimsori [14]

Answer:

i think its d frequency

Explanation:

hz on a multimeter means frequency setting

6 0

3 years ago

What is 222 divided by 11.2

valentinak56 [21]

Answer:

The answer of this question is 19.89142857

3 0

3 years ago

Read 2 more answers

Calculate the number of 12 V batteries (capacity 120 Ah) needed to run a 3 kW DC motor that operates in 240 V. How many hours th

Mrac [35]

Answer:

20 batteries
9.6 hours

Explanation:

To obtain 240 V from 12 V batteries they must be connected in series. The number needed is ...

240/12 = 20 . . . batteries needed

__

The current draw will be ...

(3000 W)/(240 V) = 12.5 A

Then the time available from the battery stack is ...

(120 Ah)/(12.5 A) = 9.6 h

The motor can run 9.6 hours from the series connection.

3 0

3 years ago