Newton's second law allows us to find the force applied to the student so that it has an upward acceleration of 27.4 m / s² is:
F = 1.94 10³ N
Newton's second law says that the force is proportional to the product of the mass and the acceleration of the body.
∑ F = m a
Where F is the force, m the mass and the acceleration of the body.
A free body diagram is a diagram of the forces without the details of the bodies, in the attachment we have a free body diagram of the system.
They indicate that the student's mass is 52.1 kg and his acceleration is 27.4 m / s², let's write Newton's second law.
F - W = ma
F = m a + W
Body weight is.
W = mg
F = m (a + g)
We calculate.
F = 52.1 (27.4+ 9.8)
F = 1.94 10³ N
In conclusion using Newton's second law we can find the force applied to the student is:
F = 1.94 10³ N
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Internal thermal energy is given as
so it will depend on the product of mass, specific heat capacity and temperature.
so here we know that both blocks are identical with same initial temperature
So the block with larger mass must have more internal energy
So here the correct answer would be the block with mass 1000g
block with mass 1000 g must have more internal energy
Answer:
Explanation:
mass of bob = M
string is fixed at C, at position A the string is horizontal and at position B teh string is vertical.
Let the length of the string is L.
At the point C, it has maximum potential energy which is equal to
U = M x g x L ..... (1)
At the position B, it has maximum kinetic energy and the velocity is v.
K = 1/2 Mv² ...... (2)
According to the conservation of energy
The potential energy at the position A is equal to the kinetic energy at position B.
M x g x L = 1/2 M x v²
v² = 2 x g x L
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