Answer:
Energy.
Explanation:
Waves can travel through medium and can be without medium.
In electromagnetic waves the energy travels through vibration of electric field and magnetic field while in sound waves energy is transferred through vibration of particles through which sound waves are travelling or though vibration of air particles.
<span>The answer is letter C.
Reflecting telescopes are more powerful than refracting telescopes. These are also called as reflectors which serves an optical telescope that uses a single or combination of curved mirrors. These mirrors then reflect light and form an image. It is designed for very large diameter objects and are mostly considered as major telescopes in the field of astronomy. They were used as an alternative for refracting telescopes during the 17th century because they suffer less chromatic aberrations than a refracting telescope does. <span>
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Answer:
12500 V
Explanation:
The electric field in the gap of a parallel-plate capacitor is uniform, so the following relationship between electric field strength, potential difference and distance can be used:
![\Delta V = E d](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20E%20d)
where
is the potential difference between the plates
E is the electric field strength
d is the distance between the plates
For the capacitor in this problem, we have
![E=5.00\cdot 10^6 V/m](https://tex.z-dn.net/?f=E%3D5.00%5Ccdot%2010%5E6%20V%2Fm)
![d = 2.50 mm = 2.50\cdot 10^{-3} m](https://tex.z-dn.net/?f=d%20%3D%202.50%20mm%20%3D%202.50%5Ccdot%2010%5E%7B-3%7D%20m)
Substituting, we find
![\Delta V = (5.00\cdot 10^6)(2.50\cdot 10^{-3})=12500 V](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20%285.00%5Ccdot%2010%5E6%29%282.50%5Ccdot%2010%5E%7B-3%7D%29%3D12500%20V)
Answer:
0.1 s
Explanation:
The net force on the log is F - f = ma where F = force due to winch = 2850 N, f = kinetic frictional force = μmg where μ = coefficient of kinetic friction between log and ground = 0.45, m = mass of log = 300 kg and g = acceleration due to gravity = 9.8 m/s² and a = acceleration of log
So F - f = ma
F - μmg = ma
F/m - μg = a
So, substituting the values of the variables into the equation, we have
a = F/m - μg
a = 2850 N/300 kg - 0.45 × 9.8 m/s²
a = 9.5 m/s² - 4.41 m/s²
a = 5.09 m/s²
Since acceleration, a = (v - u)/t where u = initial velocity of log = 0 m/s (since it was a rest before being pulled out of the ditch), v = final velocity of log = 0.5 m/s and t = time taken for the log to reach a speed of 0.5 m/s.
So, making t subject of the formula, we have
t = (v - u)/a
substituting the values of the variables into the equation, we have
t = (v - u)/a
t = (0.5 m/s - 0 m/s)/5.09 m/s²
t = 0.5 m/s ÷ 5.09 m/s²
t = 0.098 s
t ≅ 0.1 s