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mars1129 [50]
3 years ago
6

The transfer of energy between two objects that are physically touching is called

Physics
1 answer:
Nuetrik [128]3 years ago
7 0
The answer is conduction
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A uniformly charged ring of radius 10.0 cm has a total charge of 50.0 μC Find the electric field on the axis of the ring at 30.0
Grace [21]

Answer: 4.27 *10^6 N/C

Explanation: In order to calculate the electric field along the axis of charged ring we have to use the following expression:

E=k*x/(a^2+x^2)^3/2    where a is the ring radius and x the distance to the point measured from the center of the ring.

Replacing the data we have:

E= (9* 10^9* 0.3* 50 * 10^-6)/(0.1^2+0.3^2)^3/2

then

E=4.27 * 10^6 N/C

8 0
3 years ago
Match the type of boundary with its characteristic.
olga_2 [115]

At Divergent boundary, Crust is created.

At Convergent boundary, Crust is destroyed.

At Transform boundary, Crust is neither created nor destroyed.

<h3>What occurs at Divergent, Convergent and Transform boundary?</h3>

A divergent boundary occurs when two tectonic plates move away from each other. At this boundary, new oceanic crust is created.

Convergent boundaries are those boundaries where two plates are pushing into each other. These boundaries are pushing one of the plates under the other and back into the mantle to melt.

Transform boundaries are places where plates slide sideways past each other. At this boundary, Crust is neither created nor destroyed.

Learn more about boundary here: brainly.com/question/14298823

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7 0
2 years ago
In a carnival booth, you can win a stuffed giraffe if you toss a quarter into a small dish. the dish is on a shelf above the poi
Georgia [21]

components of the speed of the coin is given as

v_x = v cos60

v_x = 6.4 cos60 = 3.2 m/s

v_y = vsin60

v_y = 6.4 sin60 = 5.54 m/s

now the time taken by the coin to reach the plate is given by

t = \frac{\delta x}{v_x}

t = \frac{2.1}{3.2}

t = 0.656 s

now in order to find the height

h = vy * t + \frac{1}{2} at^2

h = 5.54 * 0.656 - \frac{1}{2}*9.8*(0.656)^2

h = 1.52 m

so it is placed at 1.52 m height

3 0
3 years ago
Suppose a particle moves along a straight line with velocity v(t)=t2e−2tv(t)=t2e−2t meters per second after t seconds. How many
dimulka [17.4K]

Explanation:

It is given that,

Velocity of the particle moving in straight line is :

v(t)=t^2e^{-2t}\ m/s

We need to find the distance (x)  traveled by the particle during the first t seconds. It is given by :

x=\int\limits {v.dt}

x=\int\limits {t^2e^{-2t}dt}

Using by parts integration, we get the value of x as :

x=\dfrac{-(2t^2+2t+1)e^{-2t}}{4}\ meters

Hence, this is the required solution.

6 0
3 years ago
Which of the following best characterizes an electron?
barxatty [35]
A, electrons are negatively charged and do orbit around the nucleons
4 0
3 years ago
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