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Andrews [41]
3 years ago
7

A 11 g plastic ball is moving to the left at 29 m/s. How much work must be done on the ball to cause it to move to the right at

29 m/s ? Express your answer using two significant figures.
Physics
1 answer:
Rasek [7]3 years ago
8 0

Answer:

4.25 J

Explanation:

Given that

mass of plastic ball = 11 g

Mass of plastic ball = 0.011 kg

velocity of ball = 29 m/s

We know that from work power energy theorem

W_{all}=Change\ in\ kinetic\ energy\ of\ system

We know that kinetic energy of moving mass given as

KE=\dfrac{1}{2}mv^2

Now by pitting the values

KE=\dfrac{1}{2}mv^2

KE=\dfrac{1}{2}\times 0.011\times 29^2

KE= 4.25 J

So the work done on the ball is 4.25 J

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seraphim [82]

Answer:

51kg

Explanation:

w=FxS

2500=Fx5

F=2500/5=500

mass = 500/9.8 = 51kg

7 0
1 year ago
A meter stick balances at the 50.0-cm mark. If a mass of 50.0 g is placed at the 90.0-cm mark, the stick balances at the 61.3-cm
Airida [17]

Answer:

126.99115 g

Explanation:

50 g at 90 cm

Stick balances at 61.3 cm

x = Distance of the third 0.6 kg mass

Meter stick hanging at 50 cm

Torque about the support point is given by (torque is conserved)

mgl_1=Mgl_2\\\Rightarrow M=\dfrac{ml_1}{l_2}\\\Rightarrow M=\dfrac{50\times (61.3-90)}{50-61.3}\\\Rightarrow M=126.99115\ g

The mass of the meter stick is 126.99115 g

6 0
2 years ago
Read 2 more answers
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Grace [21]

Answer:

Action and reaction are equal but act in opposite directions

4 0
3 years ago
Read 2 more answers
Tire or false
spayn [35]
1 and 4 are tire.
2 and 3 are not.
8 0
2 years ago
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Phantasy [73]
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Espero que esto te ayude y no me haya confundido
7 0
2 years ago
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