To solve the problem we will simply perform equivalence between both expressions. We will proceed to place your units and develop your internal operations in case there is any. From there we will compare and look at its consistency
At the same time we have that
Therefore there is not have same units and both are not consistent and the correct answer is B.
Answer:
Explanation:
First of all, we can find the speed of the sound wave, which is given by:
where
f = 645 Hz is the frequency
is the wavelength
Substituting,
Now we can find the temperature of the air by using the following relationship:
where T is the temperature in Celsius degrees. Since we know v = 322.5 m/s, we can re-arrange the formula to find the temperature:
Answer:
b) = 4.88 cm
, c)
’= 1/M (m₁ d₁ + m₃ d₃) and d)
’= 1.88 cm
Explanation:
The definition of mass center is
= 1/M ∑ xi mi
Where mi, xi are the mass and distance from an origin for each mass and M is the total mass of the object.
Part b
Apply this equation to our case.
Body 1
They give us the mass (m₁ = 24 g) and the distance (d₁ = 1.1 cm) from the origin at the far left
Body 2
They give us the mass (m₂ = 12.g) and the distance relative to the distance of the body 1, let's look for the distance from the left end (origin)
D₂ = d₁ + d₂
D₂ = 1.1 + 1.9
D₂ = 3.0 cm
Body 3
Give the mass (m₃ = 56 g) and the position relative to body 2, let's find the distance relative to the origin
D₃ = D₂ + d₂
D₃ = 3.0 + 3.9
D₃ = 6.9 cm
With this data we substitute and calculate the center of mass
M = m₁ + m₂ + m₃
M = 24 + 12 + 56
M = 92 g
= 1/92 (1.1 24 + 3.0 12 + 6.9 56)
= 1/92 (448.8)
= 4,878 cm
= 4.88 cm
This distance is from the left end of the bar
Par c)
In this case we are asked for the same calculation, but the reference system is in the center marble, we have to rewrite the distance with the reference system in this marble.
Body 1
It is at d1 = -1.9 cm
It is negative for being on the left and the value is the relative distance of 1 to 2
Body 2
d2 = 0 cm
The reference system for her
Body 3
d3 = 3.9 cm
Positive because that is to the left of the reference system and is the relative distance between 2 and 3
Let's write the new center of mass (xcm')
’= 1/M (m₁ d₁ + m₂ d₂ + m₃ d₃)
’= 1/M (m₁ d₁ + m₃ d₃)
Part d) Let's calculate the value of the center of mass
’= 1/92 ((24 (-1.9) +56 3.9)
’= 1/92 (172.8)
’= 1.88 cm
This distance is to the right of the central marble
Answer:
V_{average} = , V_{average} = 2 V
Explanation:
he average or effective voltage of a wave is the value of the wave in a period
V_average = ∫ V dt
in this case the given volage is a square wave that can be described by the function
V (t) =
to substitute in the equation let us separate the into two pairs
V_average =
V_average =
V_{average} =
we evaluate V₀ = 4 V
V_{average} = 4 / 2)
V_{average} = 2 V