Answer:
0.63m
Explanation:
Volume expansivity = change in volume/original volume×temp change
Volume expansivity p = 3x
p = ∆V/V∆t
x is the linear expansivity
Given
x = 6 x 10^-4
p = 3x
p = 3(6 x 10^-5)
p = 18×10^-5
Volume = 100m³
∆t = 45-10 = 35°C
Required
Change in volume ∆V
Substitute the given values into the formula
18×10^-5 = ∆V/100(35)
18×10^-5 =∆V/3500
∆V = 3500×0.00018
∆V = 0.63m
Hence the increase in volume of the Mercury is 0.63n
It will be 80 miles and it can be done only in 16 min
Answer:
1) The car is slowing down
2) A = 40N forward & B = 25N up
Explanation:
Whenever you're dealing with forces on moving objects, it is important to look at each of the numbers and the directions they're going in.
With the racecar, we see it has four forces on it, 2,000 N up and down, 8,000 back, and 6,000 N forward. Now, each of these forces are going in their respective directions, but they are most in comparison with the force going in the opposite direction (vertical axis, horizontal axis). The two 2,000 N forces will cancel each other out since there is an equal force in both directions, causing a net force of <u>0 N on the vertical axis</u>. This is because the car is most likely moving on a flat surface. As for the horizontal axis, we simply subtract 6,000 & 8,000 to get a net force of <u>-2,000 N in the backwards direction</u>, telling us that the car is slowing down.
As for the boxes, we see the same vertical and horizontal axes, but separated to each box. Box A has a net force of <u>40 N in the forward direction</u> and Box B has a net force of <u>25 N in the upward direction</u>.
We don't know, and we don't have enough information to calculate it.
The weight of the 60kg load is (m g) = 588 Newtons.
IF Hari wanted to<em> lift </em>the load 12m <em>straight up</em>, he would have to do
(Force x distance) = (588 N) x (12 m) = 7,056 Joules of work.
But to drag it, he has to provide enough force to balance out the force of friction, and we don't know how much that is. It depends on the weight of the load, the shape of the load, the smoothness of the part of the load that sits on the ground, and the smoothness of the ground. But the only thing we know is the weight of the load.