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lys-0071 [83]
3 years ago
10

2. A rock is shot straight up into the air with a slingshot that had been stretched 0.30 m. Assume

Physics
2 answers:
Darina [25.2K]3 years ago
5 0
E because the other guy said so I’m not sure
Luba_88 [7]3 years ago
4 0

Answer:

e

Explanation:

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50-g of hot water at 65 degree C is poured into a cavity in a very large block of ice at 0 degrees C. The final temperature of t
Mariulka [41]

Answer:

m = 40.88 g

Explanation:

Given data:

We know that Ice at zero degree celcius convert into liquid form by observing heat

latent heat of fusion = 79.5 cal/g

heat required or relaesed to convert 50 gram of water at 65 degree  c to zero degree celcius

let mass of ice is m

50 \times\ (1 cal/g) \times (65-0) = m(79.5) cal/g

where 1 cal/g  os specific heat of water

solving for m

m = \frac{50\times 65}{79.5} g

m = 40.88 g

6 0
3 years ago
6. What is not an example of mechanical energy?
zhannawk [14.2K]

Answer:

the answer to your question is c

3 0
2 years ago
4. Which activity would be BEST for prolonged training within your target heart rate zone?
valina [46]
I am sorry I would answer this questions but I don’t have the options of the heart rates so I can give you the best answer
6 0
3 years ago
A 60.0-kg skater begins a spin with an angular speed of 6.0 rad/s. By changing the position of her arms, the skater decreases he
juin [17]

The skater's final angular speed is equal to 12 rad/s.

When implemented to angular momentum, the regulation of conservation means that the momentum of a rotating item is no longer exchanged until some form of external torque is carried out. Torque, in this sense, can check with any outside pressure that acts upon the object for the purpose to twist or rotate.

The law of conservation of angular momentum states that once no external torque acts on an item, no trade of angular momentum will occur. The angular momentum of a machine is conserved as long as there may be no net external torque performing on the machine.

In angular kinematics, the conservation of angular momentum refers back to the tendency of a device to keep its rotational momentum inside the absence of outside torque. For a round orbit, the system for angular momentum is (mass) ×(pace) ×(radius of the circle): (angular momentum) = m × v × r.

Learn more about angular momentum here brainly.com/question/7538238

#SPJ4

7 0
2 years ago
Problem 2: (15 pts) A 10-m high cylindrical container is half-filled at the bottom with water of density =1000 kg/m3 while the t
Step2247 [10]

Answer:

\Delta p = 90.7 kPa

Explanation:

specific gravity of oil is = \frac{\rho_{oil}}{\rho_w}

\rho_{oil} = 0.85*1000 = 850 kg/m3

we know that

change in pressure  for oil is given as

\Delta p = \rho gh

here density and h is for oil

\Delta p = 850*5 *9.81 = 41,692.5 kPa

change in pressure  for WATER is given as

\Delta p = \rho gh

here density is for water and h is for water

\Delta p = 1000*5 *9.81 = 49,050 kPa

pressure change due to both is given as

\Delta p = 41692.3 + 49050 = 90742.5 N/m2

\Delta p = 90.7 kPa

8 0
3 years ago
Read 2 more answers
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