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mario62 [17]
3 years ago
14

For your science fair project you need to design a diffraction grating that will disperse the visible spectrum (400-700 nm) over

30.0∘ in first order.
Physics
1 answer:
elixir [45]3 years ago
3 0

Answer:

Explanation:

If d be the distance between two lines , for bright fringe in first order

d sinθ = λ

700 nm must be positioned at 30⁰

d sin30 = 700 x 10⁻⁹

d = 7 x 10⁻⁷ / .5

= 14 x 10⁻⁷

= 14 x 10⁻⁷

no of lines per m

1/ 14 x 10⁷

= 7.14 x 10⁵

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What is the work done when a 400.n force is use to lift a 400.n object 3.5 meters strait up
alexandr1967 [171]

Answer:

i think it's 1400

Explanation:

w = Force x displacement

w = 400 x 3.5

3 0
3 years ago
A device known as Atwood's machine consists of two masses hanging from the ends of a vertical rope that passes over a pulley. As
Vlad [161]

Answer:

a= \frac{(m_{1} -m_{2} )*g}{m_{1} +m_{2} }

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Explanation:

We apply Newton's second law:

∑F = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Problem development

M1 free body diagram : Look at the attached graphic

∑F = m₁*a

W₁ -T= m₁*a

W₁ - m₁*a = T  Equation 1

M2 free body diagram :Look at the attached graphic

∑F = m₂*a

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W₂ + m₂*a = T  Equation 2

Equation 1  = Equation 2

W₁ - m₁*a = W₂ + m₂*a

W₁ - W₂ =  m₁*a + m₂*a

m₁*g -m₂*g = a* (m₁ + m₂)

a = (m₁*g -m₂*g) / (m₁ + m₂)

a= \frac{(m_{1} -m_{2} )*g}{m_{1} +m_{2} }

Calculation of the tension in the rope (T)

We replace a in the equation 2

W₂ + m₂*a = T

W₂ + m₂*g*(m₁ -m₂) /  (m₁ + m₂) = T

m₂*g + m₂*g*(m₁ -m₂) /  (m₁ + m₂) = T

m₂*g( (1+ (m₁ -m₂)) /  (m₁ + m₂) = T

m₂*g (1+m₁ -m₂) /  (m₁ + m₂) = T

T= \frac{m_{2}g(1+m_{1} -m_{2} ) }{m_{1}+m_{2}  }

7 0
3 years ago
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Vaselesa [24]

Answer:

hi there!!

Explanation:

Nickel  149 pm

Cobalt  152 pm

Calcium  194 pm

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So Potassium is the correct answer

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167•F which is c


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