Answer: Partial pressures are 0.6 MPa for nitrogen gas and 0.4 MPa for carbon dioxide.
Explanation: <u>Dalton's</u> <u>Law</u> <u>of</u> <u>Partial</u> <u>Pressure</u> states when there is a mixture of gases the total pressure is the sum of the pressure of each individual gas:
The proportion of each individual gas in the total pressure is expressed in terms of <u>mole</u> <u>fraction</u>:
= moles of a gas / total number moles of gas
The rigid tank has total pressure of 1MPa.
molar mass = 14g/mol
mass in the tank = 2000g
number of moles in the tank: = 142.85mols
molar mass = 44g/mol
mass in the tank = 4000g
number of moles in the tank: = 90.91mols
Total number of moles: 142.85 + 90.91 = 233.76 mols
To calculate partial pressure:
For Nitrogen gas:
= 0.6
For Carbon Dioxide:
0.4
Partial pressures for N₂ and CO₂ in a rigid tank are 0.6MPa and 0.4MPa, respectively.
Answer:
Production Function : TFSq = f { ingredient 1 ...... ing. i }
Increasing/ Constant/ Increasing Returns to Scale :
Output change > / = / < Input change respectively
Explanation:
Production Function is the relationship between production inputs & outputs, given technology. It denotes the maximum output that can be generated with given inputs.
Tutti Frutti Smoothie [TFS] quantity = Function of {Ingredient1.....ingredient i}
Returns to Scale represents change in output when all inputs change in same proportion.
- Constant Returns to Scale [CRS] : Output Change = All inputs change
- Increasing Returns to Scale [IRS] : Output Change > All inputs change
- Negative Returns to Scale [NRS] : Output Change < All inputs change
When all inputs (ingredients) change by same proportion i.e get twice 2X :- If output of Tutti Frutti Smoothie increases by > 2X i.e 3X - IRS. If it increases equal ie 2X - CRS. If it increases lesser i.e 1.5X - CRS.
Answer:
Question 1 A 1020 Cold-Drawn steel shaft is to transmit 20 hp while rotating at 1750 rpm. Calculate the transmitted torque in lbs. in. Ignore the effect of friction. Answer with three decimal points. 60.024 Question 2 Based on the maximum-shear-stress theory, determine the minimum diameter in inches for the shaft in Q1 to provide a safety factor of 3. Assume Sy = 57 Kpsi. Answer with three decimal points. 0.728 Question 3 If the shaft in Q2 was made of ASTM 30 cast iron, what would be the factor of safety? Assume Sut = 31 Kpsi, Suc = 109 Kpsi 0 2.1 O 2.0 O 2.5 0 2.4 2.3 O 2.2
Explanation:
hope it helps