Answer:
value of the rate constant is 80 mg/L-hr
Explanation:
given data
concentration of compound Cao = 90 mg/l
Ca = 10 mg/L
time = 1 hour
solution
we use here zero order reaction rate flow
-rA = K Ca
= K
-d Ca = k dt
now we will integrate it on the both side by Cao to ca we get
solve it we get
cao - Ca = K t
put here value and we get K
90 - 10 = K 1
K = 80 mg/L-hr
so value of the rate constant is 80 mg/L-hr
control volume
differential approach
control volume:
differential approach:
i dont want too
461 C
862 F
The specific gas constant for CO2 is
R = 189 J/(kg*K)
Using the gas state equation:
p * v = R * T
T = p * v / R
v = 1/δ
T = p / (R * δ)
T = 9.3*10^6 / (189 * 67) = 734 K
734 - 273 = 461 C
461 C = 862 F
whats
the question choices
the wire that can carry much current is AWG 24