Answer:
hope this help by the way found off of yahoo
Explanation:
Calculate the number of grams of nitrogen dioxide that are produced from
4 moles of nitric oxide.
2NO(g) + O2(g) -->2NO2(g)
I really need help with this... I need to know how to work it too... I can balance it out but not sure about grams... This is it balanced out with 4 moles of nitric oxide
4NO(g) + 2O2(g) ->4NO2(g) please help and explain i want to learn this
Weak base: [OH⁻] = √Kb.C
pKb = 4.2
c = concentration
MM Amphetamine (C9H13N) = 135.21 g/mol
c = 215 mg/L = (0.215 g : 135,21 g/mol) / L = 0.00159 mol/L = 1.59 x 10⁻³ mol/L
![\tt [OH^-]=\sqrt{10^{-4.2}\times 1.59\times 10^{-3}}=3.17\times 10^{-4}](https://tex.z-dn.net/?f=%5Ctt%20%5BOH%5E-%5D%3D%5Csqrt%7B10%5E%7B-4.2%7D%5Ctimes%201.59%5Ctimes%2010%5E%7B-3%7D%7D%3D3.17%5Ctimes%2010%5E%7B-4%7D)
pOH = 4 - log 3.17
pH = 14 - (4 - log 3.17)
pH = 10 + log 3.17 = 10.50
<em>the</em><em> </em><em>number</em><em> of</em><em> </em><em>nitrogen</em><em> </em><em>atoms</em><em> </em><em>in</em><em> </em><em>the </em><em>compound</em><em> </em><em>is</em><em> </em><em>two</em>
