Answer:
A. smallest wire is No. 12
Answer:
w = 10.437 kips
deflection at 1/4 span 20.83\E ft
at mid span = 1.23\E ft
shear stress 7.3629 psi
Explanation:
area of cross section = 18*76
length of span = 32 ft
moment = 334 kips-ft
we know that
moment = load *eccentricity
334 = w * 32
w = 10.437 kips
deflection at 1/4 span



= 20.83\E ft
at mid span



shear stress

Answer:
answer is
a)
3/4
Explanation:
In the last 5 meters of braking, you lose 3/4 of your speed.
Answer:
Answer to both the parts A and B are provided in the word document attached.
Explanation:
The explanation of the programs is provided in the attached file along with the screenshot of ATM application output.
Answer:
5 microhenries
Explanation:
The effective value of inductors in parallel "add" in the same way that resistors in parallel do. The value is the reciprocal of the sum of the reciprocals of the inductances that are in parallel.
10 uH ║ 10 uH = 5 uH
The effective inductance is 5 uH.