All categories

2 years ago

How many hours should I charge a 4.8v 600mah battery (I need it by today please)

Engineering

1 answer:

prohojiy [21]2 years ago

5 0

The number of hours that will be needed to charge a 600mah battery will be 1.5 hours.

<h3>What is a battery?</h3>

It should be noted that an electric battery simply means a source of electric power that consist of one or more electrochemical cells that are with external connections that are important for powering electrical devices.

It should be noted that when a battery is supplying power, then the positive terminal is the cathode while the negative terminal is the anode.

In conclusion, the number of hours that will be needed to charge a 600mah battery will be 1.5 hours.

Learn more about battery on:

brainly.com/question/16896465

#SPJ1

You might be interested in

Ventajas motor avion

Sauron [17]

Answer:

Explanation:

Usar motores eléctricos en aviones ofrece numerosas ventajas reales. A diferencia de los motores de combustión interna los motores eléctricos no necesitan aire para funcionar, lo que significa que pueden mantener toda su capacidad y potencia incluso a altitudes elevadas donde el aire es más tenue.

4 0

3 years ago

Name the famous engineer in the world

fgiga [73]

Answer:

Nikola Tesla

Explanation:

5 0

3 years ago

Read 2 more answers

The cold drawn AISI 1040 steel bar with 25-mm width and 10-mm thick has a 6- mm diameter thru hole in the center of the plate. T

4vir4ik [10]

Answer:

A) ( N ) = 1.54

B) N ( Goodman ) = 1.133, N ( Morrow) = 1.35

Explanation:

width of steel bar = 25-mm

thickness of steel bar = 10-mm

diameter = 6-mm

load on plate = between 12 kN AND 28 kN

notch sensitivity = 0.83

A ) Fatigue factor of safety based on yielding criteria

= δa + δm = $\frac{Syt}{n}$ = 91.03 + 227.58 = 490 / N

therefore Fatigue number of safety ( N ) = 1.54

δa (amplitude stress ) = kf ( Fa/A) = 2.162 * ( 8*10^3 / 190 ) = 91.03 MPa

A = area of steel bar = 190 mm^2 , Fa = amplitude load = 8 KN , kf = 2.162

δm (mean stress ) = kf ( Fm/A ) = (2.162 * 20*10^3 )/ 190 = 227.58 MPa

Fm = mean load = 20 *10^3

B) Fatigue factor of safety based on Goodman and Morrow criteria

δa / Se + δm / Sut = 1 / N

= 91.03 / 183.15 + 227.58 / 590 = 1 /N

Hence N = 1.133 ( based on Goodman criteria )

note : Se = endurance limit (calculated) = 183.15 , Sut = 590

applying Morrow criteria

N = 1 / ( δa/Se) + (δm/ δf )

= 1 / ( 91.03 / 183.15 ) + (227.58 / 935 )

= 1.35

6 0

3 years ago

A step-up transformer has 20 primary turns and 400 secondary turns. If the primary current is 30 A, what is the secondary curren

-BARSIC- [3]

150
A
Explanation:
V
s
V
p
=
N
s
N
p

(
1
)
N
refers to the number of turns
V
is voltage
s
and
p
refer to the secondary and primary coil.
From the conservation of energy we get:
V
p
I
p
=
V
s
I
s

(
2
)
From
(
1
)
:
V
s
V
p
=
900
00
3
00
=
300
∴
V
s
=
300
V
p
Substituting for
V
s
into
(
2
)
⇒
V
p
I
p
=
300
V
p
×
0.5
∴
I
p
=
150
A
Seems a big current.

3 0

3 years ago

Why is it reasonable to say that no system is 100% efficient?

Virty [35]

Generally, frictional losses are more predominant for the machines being not 100% efficient. This friction leads to the loss of energy in the form of heat, into the surroundings. Some of the supplied energy may be utilised to change the entropy (measure of randomness of the particles) of the system.

5 0

3 years ago