The load is placed at distance 0.4 L from the end of
area.
<h3>What is meant by torque?</h3>
The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. A vector quantity is torque.
Let the beam is of length L
Now the stress on both the end is the same now we can say that torque on the beam due to two forces must be zero

also, we know that stress at both ends are same


Now from two equations we have

solving the above equation we have

so the load is placed at distance 0.4 L from the end of
area.
The complete question is:
47. the beam is supported by two rods ab and cd that have cross-sectional areas of
and
, respectively. determine the position d of the 6-kn load so that the average normal stress in each rod is the same.
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Answer:
Explanation:
load = 4500lb lift height= 30 ft
time =15 s
velocity=
ft/s
velocity=2 ft/s
power = force
velocity
power=
power= 9000 lb ft/s
1 hp= 550 lb ft/s
power=
hp
Answer:
u_e = 9.3 * 10^-8 J / m^3 ( 2 sig. fig)
Explanation:
Given:
- Electric Field strength near earth's surface E = 145 V / m
- permittivity of free space (electric constant) e_o = 8.854 *10^-12 s^4 A^2 / m^3 kg
Find:
- How much energy is stored per cubic meter in this field?
Solution:
- The solution requires the energy density stored between earth's surface and the source of electric field strength. The formula for charge density is given by:
u_e = 0.5*e_o * E^2
- Plug in the values given:
u_e = 0.5*8.854 *10^-12 *145^2
u_e = 9.30777 * 10^-8 J/m^3
Explanation:
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