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mestny [16]
3 years ago
13

From the information generated in Prob. 6.4 (from your previous Aero HW#1), calculate the maximum rate of climb for the single-e

ngine light plane at sea level and at 12,000-ft altitude.
Engineering
1 answer:
soldi70 [24.7K]3 years ago
5 0

Answer:

R/C @ sea Level = 42.5 ft/s

R/C @ 12,000 ft = 24.6 ft/s

Explanation:

Given:

- From problem in 6.4:

         excess power @ sea Level = 232 hp

         excess power @ 12,000 ft = 134 hp

- Thrust delivered by the engine P = 3000 lb

Find:

Maximum rate of climb R/C @ sea Level and @12,000 ft altitude.

Solution:

- Maximum rate of climb (i.e no drag + maximum lift) @ sea level:

                  R/C = excess [email protected] level / Thrust delivered by engine P

                  R/C = 232 hp*(550) / 3000 = 42.5 ft / s

- Maximum rate of climb (i.e no drag + maximum lift) @ 12,000 ft:

                  R/C = excess [email protected] level / Thrust delivered by engine P

                  R/C = 134 hp*(550) / 3000 = 24.6 ft / s              

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A sinusoidal wave of frequency 420 Hz has a speed of 310 m/s. (a) How far apart are two points that differ in phase by π/8 rad?
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8 0
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For this question you must write a java class called Rectangle and a client class called RectangleClient. The partial Rectangle
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Explanation:

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private int x;

private int y;

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======================

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