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mestny [16]
3 years ago
13

From the information generated in Prob. 6.4 (from your previous Aero HW#1), calculate the maximum rate of climb for the single-e

ngine light plane at sea level and at 12,000-ft altitude.
Engineering
1 answer:
soldi70 [24.7K]3 years ago
5 0

Answer:

R/C @ sea Level = 42.5 ft/s

R/C @ 12,000 ft = 24.6 ft/s

Explanation:

Given:

- From problem in 6.4:

         excess power @ sea Level = 232 hp

         excess power @ 12,000 ft = 134 hp

- Thrust delivered by the engine P = 3000 lb

Find:

Maximum rate of climb R/C @ sea Level and @12,000 ft altitude.

Solution:

- Maximum rate of climb (i.e no drag + maximum lift) @ sea level:

                  R/C = excess [email protected] level / Thrust delivered by engine P

                  R/C = 232 hp*(550) / 3000 = 42.5 ft / s

- Maximum rate of climb (i.e no drag + maximum lift) @ 12,000 ft:

                  R/C = excess [email protected] level / Thrust delivered by engine P

                  R/C = 134 hp*(550) / 3000 = 24.6 ft / s              

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ELEN [110]
Yes, it will. The induction will be the same as long as it’s put back together.
5 0
4 years ago
Using the Breguet range and endurance equation, estimate the amount of kerosene
love history [14]

The amount of kerosene fuel needed for an aircraft weighing 10 metric tons to fly from Boston to Los Angeles, assuming a distance of 5,000 [km] is 10000 kg.

<h3>What is Breguet equation?</h3>

Breguet equation is used to determine the range of airplane fly in some specified set of parameters.

R=\dfrac{h_f}{g}\dfrac{L}{D}\times \eta \ln \left(\dfrac{W_{initial}}{W_{final}}\right)

Here, (L/D) is lift to drag ratio,<em> g</em> is gravitation acceleration,<em> h </em>is height and <em>W</em> is weight.

The weight of aircraft is 10 metric tons (this is the dry weight that includes passengers and cargo)  The distance of 5,000 [km], with velocity at 300 [m/s]  from Boston to Los Angeles has to be cover by the airplane.

The initial weight is 10 metric tons or 10000 kg. Thus, the final weight with total fuel burn is,

W_{final}=W_{initial}-W_{fuel}\\W_{final}=1-\dfrac{W_{fule}}{W_{initial}}

The lift-to-drag ratio is 15 and the overall efficiency is 0.3,  The standard air density at an altitude of approximately 6,000 [m] is half.

Thus, put the values, in above formula,

5000=\dfrac{6000}{9.81}(15)\times(0.3) \ln \left(\dfrac{10000}{1-\dfrac{W_{fuel}}{10000}}}\right)\\

\ln \left(\dfrac{10000}{1-\dfrac{W_{fuel}}{10000}}}\right)=1.8167\\\ln \left(\dfrac{1}{10000-W_{fuel}}}\right)=1.8167

Solving this equation, we get,

W_{fuel}=10000\rm\; kg\\

Thus, the amount of kerosene fuel needed for an aircraft weighing 10 metric tons to fly from Boston to Los Angeles, assuming a distance of 5,000 [km] is 10000 kg.

Learn more about the Breguet equation here:

brainly.com/question/15218094

#SPJ1

7 0
2 years ago
Find E[x] when x is sum of two fair dice?
Ksenya-84 [330]

Answer:

When two fair dice are rolled, 6×6=36 observations are obtained.

P(X=2)=P(1,1)=

36

1

​

P(X=3)=P(1,2)+P(2,1)=

36

2

​

=

18

1

​

P(X=4)=P(1,3)+P(2,2)+P(3,1)=

36

3

​

=

12

1

​

P(X=5)=P(1,4)+P(2,3)+P(3,2)+P(4,1)=

36

4

​

=

9

1

​

P(X=6)=P(1,5)+P(2,4)+P(3,3)+P(4,2)+P(5,1)=

36

5

​

P(X=7)=P(1,6)+P(2,5)+P(3,4)+P(4,3)+P(5,2)+P(6,1)=

36

6

​

=

6

1

​

P(X=8)=P(2,6)+P(3,5)+P(4,4)+P(5,3)+P(6,2)=

36

5

​

P(X=9)=P(3,6)+P(4,5)+P(5,4)+P(6,3)=

36

4

​

=

9

1

​

P(X=10)=P(4,6)+P(5,5)+P(6,4)=

36

3

​

=

12

1

​

P(X=11)=P(5,6)+P(6,5)=

36

2

​

=

18

1

​

P(X=12)=P(6,6)=

36

1

​

Therefore, the required probability distribution is as follows.

Then, E(X)=∑X

i

​

⋅P(X

i

​

)

=2×

36

1

​

+3×

18

1

​

+4×

12

1

​

+5×

9

1

​

+6×

36

5

​

+7×

6

1

​

+8×

36

5

​

+9×

9

1

​

+10×

12

1

​

+11×

18

1

​

+12×

36

1

​

=

18

1

​

+

6

1

​

+

3

1

​

+

9

5

​

+

6

5

​

+

6

7

​

+

9

10

​

+1+

6

5

​

+

18

11

​

+

3

1

​

=7

E(X

2

)=∑X

i

2

​

⋅P(X

i

​

)

=4×

36

1

​

+9×

18

1

​

+16×

12

1

​

+25×

9

1

​

+36×

36

5

​

+49×

6

1

​

+64×

36

5

​

+81×

9

1

​

+100×

12

1

​

+121×

18

1

​

+144×

36

1

​

=

9

1

​

+

2

1

​

+

3

4

​

+

9

25

​

+5+

6

49

​

+

9

80

​

+9+

3

25

​

+

18

121

​

+4

=

18

987

​

=

6

329

​

=54.833

Then, Var(X)=E(X

2

)−[E(X)]

2

=54.833−(7)

2

=54.833−49

=5.833

∴ Standard deviation =

Var(X)

​

=

5.833

​

=2.415

4 0
3 years ago
What is a thermal reservoir?
Mekhanik [1.2K]

Answer:

Explanation:

Thermal reservoir:

   It is the body which have infinite amount of heat capacity and store large amount of heat.The temperature of thermal reservoir is constant and does not change with time.The temperature of thermal reservoir is not change even heat is going out from reservoir or heat going inside the reservoir.The temperature of thermal reservoir remains constant and does not depend on the surroundings.

7 0
4 years ago
A series circuit has 4 identical lamps. The potential difference of the energy source is 60V. The total resistance of the lamps
Alexxx [7]

Answer:

I=3A

Explanation:

From the question we are told that:

Number of lamps N=4

Potential difference V=60v

Total Resistance of the lamp is R= 20ohms

Generally the equation for Current I is mathematically given by

 I=\frac{V}{R}

 I=\frac{60}{20}

 I=3A

8 0
3 years ago
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