Answer:
R/C @ sea Level = 42.5 ft/s
R/C @ 12,000 ft = 24.6 ft/s
Explanation:
Given:
- From problem in 6.4:
excess power @ sea Level = 232 hp
excess power @ 12,000 ft = 134 hp
- Thrust delivered by the engine P = 3000 lb
Find:
Maximum rate of climb R/C @ sea Level and @12,000 ft altitude.
Solution:
- Maximum rate of climb (i.e no drag + maximum lift) @ sea level:
R/C = excess [email protected] level / Thrust delivered by engine P
R/C = 232 hp*(550) / 3000 = 42.5 ft / s
- Maximum rate of climb (i.e no drag + maximum lift) @ 12,000 ft:
R/C = excess [email protected] level / Thrust delivered by engine P
R/C = 134 hp*(550) / 3000 = 24.6 ft / s
