Answer:
C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + 4CO2(g)
Explanation:
When aqueous sugar (sucrose) react with water in the presence of yeast, the following products are obtained as shown in the equation below:
C12H22O11(aq) + H2O(l) —> C2H5OH(aq) + CO2(g)
Now, we shall balance the equation as follow:
There are a total of 24 atoms of H on the left side and 6 atoms on the right side. It can be balance by putting 4 in front of C2H5OH as shown below:
C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + CO2(g)
There are a total of 9 atoms of C on the right side and 12 atoms on the left side. It can be balance by putting 4 in front of CO2 as shown below:
C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + 4CO2(g)
Now the equation is balanced.
<h2>Nucleosynthesis.</h2>
Explanation:
A. the Big Bang occurred; the Big Crunch occurred
Nucleosynthesis is the process by which new atomic nucleus are formed from pre-existing protons and neutrons.
According to cosmic theories, the nucleosythesis began one minute after the occurrence of Big bang and will end with the big Crunch.
The Big bang theory describes all the processes by which the universe came into existence while the big crunch theory explains how universe will come to an end. A
The coefficient for NaNO₃ = 6
<h3>Further explanation
</h3>
Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:
• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.
• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product
• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1
Reaction
AI(NO₃)₃ +Na₂SO₄ →
Al₂(SO₄) +
NaNO₃
give coefficient
aAI(NO₃)₃ +bNa₂SO₄ →
Al₂(SO₄)₃ +c
NaNO₃
Al, left=a, right=2⇒a=2
N, left=3a, right=c⇒3a=c⇒3.2=c⇒c=6
Na, left=2b, right=c⇒2b=c⇒2b=6⇒b=3
The equation becomes :
2AI(NO₃)₃ +3Na₂SO₄ →
Al₂(SO₄)₃ +6NaNO₃
Answer:
10 Litre
Explanation:
Given that ::
v1 = 25L ; n1 = 1.5 mole ; v2 =? ; n2 = (1.5-0.9) = 0.6 mole
Using the relation :
(n2 * v1) / n1 = (n2 * v2) / n2
v2 = (n2 * v1) / n1
v2 = (0.6 mole * 25 Litre) / 1.5 mole
v2 = 15 / 1.5 litre
v2 = 10 Litre
