All categories

4 years ago

Salt acts as an antifreeze. a. True b. False

Chemistry

2 answers:

Tomtit [17]4 years ago

8 0

Answer:

It's true

Explanation:

An example can be observed when the people add salt on the road surface to avoid icing. The salt water mixture is frozen at approximately a temperature of -21°C and not at a temperature of 0°C as it would be in the case of water. Salt when dissolved in water releases heat, thereby contributing to defrost ice. This is the same principle that is used for car antifreeze, which is to lower the freezing point.

r-ruslan [8.4K]4 years ago

5 0

A. I think that is the a answer. Not to sure

You might be interested in

What is the Percent yield is 4.65 got copper is produced by 1.87 percent yield is 4.65 got copper is produced when 1.87 grams of

marta [7]

Answer:

Percent yield = 69.4%

Explanation:

Given data:

Percent yield = ?

Actual yield of copper = 4.65 g

Mass of aluminium = 1.87 g

Mass of copper sulfate = excess

Solution:

Chemical equation:

2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu

Number of moles of Aluminium:

Number of moles = mass/ molar mass

Number of moles = 1.87 g/27 g/mol

Number of moles = 0.07 mol

Now we will compare the moles of Al with copper.

Al : Cu

2 : 3

0.07 : 3/2×0.07 =0.105 mol

Mass of Copper:(Theoretical yield)

Mass = Number of moles × molar mass

Mass = 0.105 mol × 63.5 g/mol

Mass = 6.7 g

Percent yield:

Percent yield = Actual yield / theoretical yield × 100

Percent yield = 4.65 g/ 6.7 g × 100

Percent yield = 69.4%

4 0

4 years ago

Aerosol cans have a label that warns the user not to use them above a certain temperature and not to dispose of them by incinera

Alex73 [517]

Answer:

1.40 atm

Explanation:

To answer this question we can use<em> Gay-Lussac's law</em>, which states:

P₁T₂=P₂T₁

When volume and number of moles remain constant.

P₁ = 1.11 atm

T₁ = 23°C ⇒ 23+273.16 = 296.16 K

T₂ = Boiling point of water = 100 °C ⇒ 100+273.16 = 373.16 K

P₂ = ?

We <u>put the known data in the equation and solve for P₂</u>:

1.11 atm * 373.16 K = P₂ * 296.16 K

P₂ = 1.40 atm

4 0

3 years ago

What is The mass of 1 gram

NARA [144]

One kilogram is the answer

3 0

3 years ago

Read 2 more answers

What is the pH of a solution with an [H+] of (a) 5.4 x 10-10, (b) 4.3 x 10-5, (c) 5.4 x 10-7?

IgorLugansk [536]

Answer:

a. 9.2

b. 4.4

c. 6.3

Explanation:

In order to calculate the pH of each solution, we will use the definition of pH.

pH = -log [H⁺]

(a) [H⁺] = 5.4 × 10⁻¹⁰ M

pH = -log [H⁺] = -log 5.4 × 10⁻¹⁰ = 9.2

Since pH > 7, the solution is basic.

(b) [H⁺] = 4.3 × 10⁻⁵ M

pH = -log [H⁺] = -log 4.3 × 10⁻⁵ = 4.4

Since pH < 7, the solution is acid.

(c) [H⁺] = 5.4 × 10⁻⁷ M

pH = -log [H⁺] = -log 5.4 × 10⁻⁷ = 6.3

Since pH < 7, the solution is acid.

3 0

3 years ago

If a sample of magnesium with a mass of 35.0 grams reacts with 35.0 grams of oxygen how much magnesium oxide will be produced?

slamgirl [31]

Answer:

58.0 g of MgO

Explanation:

in a perfect world, 70 g, however we don't live in a perfect world

The equation of reaction

2Mg + O₂ --> 2MgO

first find which element is limiting:

35 g x 1 mol/24.3 g of Mg x 2 mol of MgO/ 2 mole of Mg = 1.44 moles of MgO

35 g x 1 mol/32g of Mg x 2 mol of MgO/ 1 mole of O₂ = 2.1875 moles of MgO

This means Mg is the limiting factor, so you will be using this moles to find grams of MgO

1.44 mols of MgO x 40.3 g of MgO/ 1 mol = 58.0 g of MgO

8 0

3 years ago