All categories

4 years ago

Salt acts as an antifreeze. a. True b. False

Chemistry

2 answers:

Tomtit [17]4 years ago

8 0

Answer:

It's true

Explanation:

An example can be observed when the people add salt on the road surface to avoid icing. The salt water mixture is frozen at approximately a temperature of -21°C and not at a temperature of 0°C as it would be in the case of water. Salt when dissolved in water releases heat, thereby contributing to defrost ice. This is the same principle that is used for car antifreeze, which is to lower the freezing point.

r-ruslan [8.4K]4 years ago

5 0

A. I think that is the a answer. Not to sure

You might be interested in

All of the following are characteristics of matter except

AURORKA [14]

The answer is A...matter cannot disappear and reappear

5 0

3 years ago

Read 2 more answers

The intensity of a sound describes

baherus [9]

The intensity of a sound describes <em>its loudness at a particular distance</em><em />

Sound intensity is factored by the ear's sensitivity to the particular frequencies contained in a sound

Sound loudness describes the strength of the ear's perception of a sound.

These two points being said, if the ear is more sensitive to a frequency, that sound will be louder to us than sounds at different frequencies that might not be as sensitive to our ears. <em>So, the more intense the sound, the louder it is ;)</em>

Thank you for your question! I hope this helped! Have an amazing day! :D

5 0

3 years ago

A polymer sample combines five different molecular-weight fractions, each of equal weight. The molecular weights of these fracti

kakasveta [241]

Answer:

Mn = 43,783

Mw = 60,000

Mz = 73,333

narrow distribution = 1.37

Explanation:

The molecular weights of these fractions increase from 20,000 to 100,000 in increments of 20,000. This means their Mi is respectively: (The molar weight (Mi) of the fractions)

Fraction 1 : Mi = 20 *10^3

Fraction 2: Mi = 40 *10^3

Fraction 3 : Mi = 60 *10^3

Fraction 4: Mi = 80 *10^3

Fraction 5 : Mi = 100 *10^3

The ΣMi = 300*10^-3

The Wi (mass of the fractions is for all the fractions the same, let's say 1)

So Wi = 1+1+1+1+1 = 5

Since number of moles = mass / Molar mass

The number of moles is respectively: ni = Wi/Mi (x10^5)

Fraction 1 : ni = Wi/Mi = 1/20000 = 5

Fraction 2: ni = 1/40000 = 2.5

Fraction 3 : ni =1/60000 = 1.67

Fraction 4: ni = 1/80000 = 1.25

Fraction 5 : ni= 1/100000 = 1

The Σni = 11.42

Mn = ΣWi/ni = 5/11.42*10^-5 = 43,783

Mw = (ΣWi * Mi)/ΣWi = 300,000 /5 = 60,000

Mz = (ΣWi * Mi²)/ΣWi *Mi = (4*10^8 +16*10^8 +36*10^8 +64*10^8 +100*10^8) /300,000 =73,333

Mz/Mn = narrow distribution =60,000/43,783 = 1.37

7 0

3 years ago

Read 2 more answers

The molar mass of barium nitrate (ba(no3)2) is 261.35 g/mol. what is the mass of 5.30 × 1022 formula units of ba(no3)2? 0.0900 g

liberstina [14]

Molar mass is the ratio of the mass to that amount of the substance. The mass of the barium nitrate in the formula unit is 23.0 grams.

The mass of a substance is the product of the molar mass of the compound and the number of moles of the compound.

Given,

Molar mass of barium nitrate = 261.35 g/mol

If, $6.022 \times 10^{23}$ have a mass of 261.35 g/mol then, $5.30 \times 10^{22}$ formula units will have a mass of,

$\begin{aligned}& = \dfrac{261.35 \times 5.30 \times 10^{22}}{6.022\times 10^{23}}\\\\&= 23.0\;\rm gm\end{aligned}$

Therefore, option C. 23.0 gm is the mass of barium nitrate.

Learn more about mass here:

brainly.com/question/24958554

6 0

2 years ago

a sample of gas initially at 0.92 atm and a temperature of 23.2 oc is heated to 40.1 oc. the resulting pressure is 1.3 atm which

Sliva [168]

From the gas law, PV=nRT we can say that P(pressure), V(volume) and T (temperature) are related to each other. The initial volume of sample is 408 ml

Given that initial volume of the sample = V1

initial pressure of the sample = 0.92atm

initial temperature of the sample = 23.2oC

Final pressure of the sample = 1.3atm

Final temperature of the sample = 40.1 oC

Final volume of the sample = 500ml = 0.5L

Using the relation P1V1/T1 = P2V2/T2

V1 = 1.3x0.5x23.2/40.1x0.92 = 15.08/36.892 = 0.408

Hence the initial volume of sample = 408 ml

To learn more about pressure click here brainly.com/question/12971272

#SPJ4

6 0

2 years ago