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fomenos
3 years ago
5

I would like some assistance

Chemistry
1 answer:
charle [14.2K]3 years ago
6 0

Answer:

#2.

Explanation:

Look at the charges. Both are positive, therefore both are cations.

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Help me please!!!!!!
Bingel [31]

Answer:

CH₄ + 2O₂ –> CO₂ + 2H₂O

The coefficients are: 1, 2, 1, 2

Explanation:

CH₄ + O₂ –> CO₂ + H₂O

The above equation can be balance by as follow:

CH₄ + O₂ –> CO₂ + H₂O

There are 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 2 before H₂O as shown below:

CH₄ + O₂ –> CO₂ + 2H₂O

There are 2 atoms of O on the left side and a total of 4 atoms on the right side. It can be balance by writing 2 before O₂ as shown below:

CH₄ + 2O₂ –> CO₂ + 2H₂O

Now, the equation is balanced.

The coefficients are: 1, 2, 1, 2

7 0
3 years ago
If you need to make 240 g lioh, how many grams of li3n must you react with excess water?
Savatey [412]
Answer is: 116,1 g of Li₃N.
Chemical reaction: Li₃N + 3H₂O → 3LiOH + NH₃.
m(LiOH) = 240g.
n(LiOH) = m(LiOH) ÷ M(LiOH).
n(LiOH) = 240 g ÷ 24 g/mol = 10 mol.
from chemical reaction: n(LiOH) : n(Li₃N) = 3 : 1.
10 mol : n(Li₃N) = 3 : 1.
n(Li₃N) = 3,33 mol.
m(Li₃N) = n(Li₃N) · M(Li₃N)
m(Li₃N) = 3,33 mol · 34,85 g/mol = 116,1 g.
8 0
3 years ago
Read 2 more answers
Give all possible, accurate, correct IUPAC names for the following compounds:
Viefleur [7K]

Answer:

A. 4-ethyl-hex-3,5-dien-2-ol.

B. 2-chloro-3-methyl-5-<em>tert</em>-butylphenol.

Explanation:

Hello there!

In this case, according to the given problems, it is possible to apply the IUPAC rules to obtain the following names:

A. 4-ethyl-hex-3,5-dien-2-ol because we have an ethyl radical at the fourth carbon and the beginning of the parent chain is on the Me (CH3) because it is closest to first OH.

B. 2-chloro-3-methyl-5-<em>tert</em>-butylphenol: because we start at the alcohol and have a chlorine atom on the second carbon, a methyl radical on the third carbon, a <em>tert</em>-butyl on the fifth carbon and the parent chain is benzene which is phenol as an alcohol.

Regards!

6 0
3 years ago
Determine the mass of CaCO3 required to produce 40.0 mL CO2 at STP. Hint use molar volume of an ideal gas (22.4 L)
cupoosta [38]

Answer:

m_{CaCO_3}=0.179gCaCO_3

Explanation:

Hello,

In this case, since the undergoing chemical reaction is:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The corresponding moles of carbon dioxide occupying 40.0 mL (0.0400 L) are computed by using the ideal gas equation at 273.15 K and 1.00 atm (STP) as follows:

PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.00 atm*0.0400L}{0.082\frac{atm*L}{mol*K}*273.15 K})=1.79x10^{-3} mol CO_2

Then, since the mole ratio between carbon dioxide and calcium carbonate is 1:1 and the molar mass of the reactant is 100 g/mol, the mass that yields such volume turns out:

m_{CaCO_3}=1.79x10^{-3}molCO_2*\frac{1molCaCO_3}{1molCO_2} *\frac{100g CaCO_3}{1molCaCO_3}\\ \\m_{CaCO_3}=0.179gCaCO_3

Regards.

3 0
4 years ago
Round to 4 significant figures.<br> 35.5450
Lelu [443]
Answer:
35.5450 will be rounded to 35.55
Explanation:
=35.5450
if the last digit is less than 5 then it will be ignored
=35.545
when the dropping digit is 5 then the retaining digit will increse by a factor of 1
=35.55
i hope this will help you
3 0
3 years ago
Read 2 more answers
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