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2 years ago

I would like some assistance

Chemistry

1 answer:

charle [14.2K]2 years ago

6 0

Answer:

#2.

Explanation:

Look at the charges. Both are positive, therefore both are cations.

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Complete the reactions to show how butanoic acid may be converted to butanal.

aksik [14]

Butanoic Acid is converted to Butanal in two steps;

Step 1: Conversion of Butanoic Acid into Butyryl Chloride:

Butanoic Acid when treated with Thionyl Chloride gives Butyryl Chloride, SO₂ and HCl gases. This step is selected due to conversion of a bad leaving group (-OH) into a good leaving group (-Cl).

Step 2: Conversion of Butyryl Chloride to Butanal:

In this reaction the Butyryl Chloride is reduced to Butanal by treating Butyryl Chloride with a mild reducing agent i.e. <span>Lithium tri </span>tert-<span>butoxy aluminum hydride.</span>

7 0

3 years ago

If an atom has 30 electrons and 35 neutrons, what is its approximate atomic mass? what is the name of this element?

Murljashka [212]

30 electrons = atomic number
Look at your periodic table. You will see zinc has a atomic number (the top number) of 30.

When you add 30 and 35 you get 65. The is the atoms ATOMIC MASS. So looking at zinc on the periodic table, look at its bottom number, which is its atomic mass. It will be 65.

This means the name of the element is ZINC.

Hope this helped!

6 0

3 years ago

How many moles of potassium are in 3.78 x 10^21 atoms of K?

lbvjy [14]

Answer: 6.3 x 10^-3 moles

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of potassium = 6.02 x 10^23 atoms

Z moles = 3.78 x 10^21 atoms

To get the value of Z, we cross multiply:

(3.78 x 10^21 atoms x 1mole) = (6.02 x 10^23 atoms x Z moles)

3.78 x 10^21 = (6.02 x 10^23 x Z)

Z = (3.78 x 10^21) ➗ (6.02 x 10^23)

Z = 0.63 x 10^-2)

Place the result in standard form

Hence, Z = 6.3 x 10^-3 moles

Thus, there are 6.3 x 10^-3 moles of potassium in 3.78 x 10^21 atoms of K.

3 0

3 years ago

Write the complete electron configuration of germanium, element 32

Ghella [55]

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2, valence shell: 4s2 3d10 4p2

6 0

3 years ago

W7L5 Stoichiometry Practice 2

Rzqust [24]

Answer:

.079 moles of Nirogen gas (N2)

Explanation:

You can see from the equaton that each ONE mole of N2 produces TWO moles of NH3.

Find the number of moles of NH3 produced.

Using Periodic Table : Mole wt of NH3 = 17 gm/mole

2.7 gm / 17 gm/mole = .1588 moles

One half as many moles of N2 are needed = .079 moles

6 0

2 years ago