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joja [24]
3 years ago
10

How can inclined planes change the amount of force to move an object? A. Increase height of the inclined plane B. Increase dista

nce of the inclined plane C. Use a wooden inclined plane instead of a metal one D. None of the above
Physics
1 answer:
mash [69]3 years ago
4 0

Answer:

Option ( B ) is correct .

Explanation:

To lift a heavy weight , inclined plane is used . Use of inclined plane , makes the task easier because instead of force mg , force mg sinθ is to be used which is less than mg . Here θ is inclination of inclined plane.

If h be the height by which weight is to be lifted

potential energy acquired by weight = mgh

work done by force mg sinθ = mgsinθ x d where d is displacement required .

mg sinθ x d = mgh  ( work done by force = potential energy stored in luggage )

d = h / sinθ

d will be more than h

Hence inclined plane increases the distance to be covered by force applied though it decreases the force itself.

Hence option ( B ) is correct .

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Read 2 more answers
Einstein and Lorentz, being avid tennis players, play a fast-paced game on a court where they stand 25.0 m from each other. Bein
Lerok [7]

Answer:

A) 199.78 J

B) 9.292x10^14 J

C) 4.2x10^7 m/s

D) 0.65 m

E) 1.13x10^-8 sec

D) 2.94x10^-9 sec

Explanation:

mass of ball = 0.0580 kg

A)

If smashed at v = 83.0 m/s, KE is

KE = 0.5mv^2

= 0.5 x 0.0580 x 83.0^2

= 199.78 J

B) if returned at v = 1.79×10^8 m/s, KE will be

KE = 0.5mv^2

= 0.5 x 0.0580 x (1.79×10^8)^2

= 9.292x10^14 J

C) during Einstein's return, velocity of rabbit relative to players is

Vr = 2.21×108 m/s

Rabbit's velocity relative to ball = 2.21×10^8 - 1.79×10^8

= 4.2x10^7 m/s

D) the rabbit's speed approaches the speed of light so we consider relativistic effect. The rabbit's measured distance is

l = l°( 1 - v^2/c^2)

= 2.5(1 - 2.21/3)

= 2.5 x 0.26

= 0.65 m

E) according to the players, the time taken by the rabbit is

t = d/v = 2.5/ 2.21×10^8

= 1.13x10^-8 sec

F) the time for rabbit as measured by rabbit is relativistic

t = t°( 1 - v^2/c^2)

= 1.13x10^-8 (1 - 2.21/3)

= 1.13x10^-8 x 0.26

= 2.94x10^-9 sec

7 0
4 years ago
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