<span><em>The answer is </em><em>A</em><em> :</em><em>" R = (First digit * 10 + second digit) * multiplier. "
</em><em>yw peasant XD</em><em>
</em></span>
The speed of the sound wave in the medium, given the data is 3900 m
<h3>Velocity of a wave </h3>
The velocity of a wave is related to its frequency and wavelength according to the following equation:
Velocity (v) = wavelength (λ) × frequency (f)
v = λf
With the above formula, we can obtain the speed of the sound wave. Details below:
<h3>How to determine speed of the sound wave</h3>
The speed of the wave can be obtained as illustrated below:
- Frequency (f) = 600 Hz
- Wavelength (λ) = 6.5 m
- Velocity (v) =?
v = λf
v = 6.5 × 600
v = 3900 m
Thus, the speed of the sound wave in the medium is 3900 m
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Answer:
<u>954.4m/s</u>
Explanation:
For a free falling object,it has constant acceleration and a changing velocity.
By using the velocity-time formula, the velocity can be obtained.
The height the rock travelled is the distance.
From,
Velocity (v) = Distance (d) / Time(t)
v = 3245m/3.4s
v = <u>954.4m/s</u>
That js the answer I got. Hope it's right.
Answer:
Spring cannot return to its original, since a part of its deformation is <u>plastic</u>, not <u>elastic</u>.
Explanation:
Physically speaking, stress is equal to the axial force divided by effective transversal area of spring. In addition, springs have usually a linear relationship between stress and strain in <u>elastic region</u>, since they are made of ductile materials. Axial force is directly proportional to axial stress, which is also directly proportional to axial strain.
Then, if force is greater than force associated with elastic limit of the spring, then spring cannot return to its original, since a part of its deformation is <u>plastic</u>, not <u>elastic</u>.
D=44.13, Horizontal velocity is unimportant. The time it takes the cannon ball to fall to the ground is the key to determining the height of the cliff. where that cannon is present.
The speed of any projectile travelling along a Horizontal velocity is known as the horizontal velocity. When a particle or object is launched into the air at an angle other than 90 degrees, it moves along the trajectory path and changes the shape of the curve to a parabolic one.
the speed at which velocity changes over time. Due to its magnitude and direction, acceleration is a vector quantity. The first derivative of velocity with respect to time or the second derivative of position with respect to time are further examples. This is called acceleration.
Distance to the ground is d = 1/2gt^2,
where g is the acceleration rate of gravity (9.80665 m/s^2)
and t = 3 secs.
d = .5×9.80665×9 = 44.13 m.
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