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MAVERICK [17]
3 years ago
13

which of the molecules listed below directly donates a nitrogen atom for the formation of urea during the urea cycle?

Chemistry
1 answer:
Vlad1618 [11]3 years ago
3 0
Aspartate directly donates a nitrogen atom from the formation of urea during the urea cycle.
The argininosuccinate synthase reeaction links aspartate and citrulline via the amino group of aspartate and provides the second nitrogen of urea.
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Greenhouse gases make up what percentage of Earth's atmosphere? A. less than 1% B. between 1% and 5% C. between 5% and 20% D. ov
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Hello there, the correct answer is:

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Imagine that one tree outside your home looks unhealthy, although all the other trees seem healthy and strong. Describe how you
Westkost [7]

Answer:

Hypothesis---experiments----results----conclusion.

Explanation:

First we make a hypothesis means a statement about why the tree looks unhealthy. In this segment of scientific method we have to test the hypothesis through experimentation. After that we have to take the readings of various parts of the tree and analyze the data to find out the problem. In the next step, we have to made the results on the basis of the data that is obtained. In the last we have to write the conclusion of the analysis and see the hypothesis.

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3 years ago
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Ymorist [56]

Answer:

physical

Explanation:

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3 0
3 years ago
The free energy of formation of nitric oxide, NO, at 1000 K (roughly the temperature in an automobile engine during ignition) is
Assoli18 [71]

<u>Answer:</u> The value of K_p for the chemical equation is 8.341\times 10^{-5}

<u>Explanation:</u>

For the given chemical equation:

N_2(g)+O_2(g)\rightarrow 2NO(g)

To calculate the K_p for given value of Gibbs free energy, we use the relation:

\Delta G=-RT\ln K_p

where,

\Delta G = Gibbs free energy = 78 kJ/mol = 78000 J/mol  (Conversion factor: 1kJ = 1000J)

R = Gas constant = 8.314J/K mol

T = temperature = 1000 K

K_p = equilibrium constant in terms of partial pressure = ?

Putting values in above equation, we get:

78000J/mol=-(8.314J/Kmol)\times 1000K\times \ln K_p\\\\Kp=8.341\times 10^{-5}

Hence, the value of K_p for the chemical equation is 8.341\times 10^{-5}

4 0
4 years ago
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Answer:

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