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3 years ago

11

a motorcycle is trying to leap across the canyon by driving horizontally off a cliff 38 m/s. Ignoring air resistance, find the s

peed with which the cycle strikes the ground on the other side

1 answer:

vaieri [72.5K]3 years ago

3 0

Answer:

46.15m/s

Explanation:

We are given that

Initial speed,u=38 m/s

Height of cliff,h=70 m

We have to find the speed with which the cycle strikes the ground at a height 35 m on the other side.

h'=35 m

Using conservation law of energy

$\frac{1}{2}mu^2+mgh=\frac{1}{2}mv^2+mgh'$

$\frac{1}{2}u^2+gh=\frac{1}{2}v^2+gh'$

Where $g=9.8m/s^2$

Substitute the values

$\frac{1}{2}(38)^2+9.8\times 70=\frac{1}{2}v^2+9.8\times 35$

$\frac{1}{2}v^2=\frac{1}{2}(38)^2+9.8\times 70-9.8\times 35=1065$

$v=\sqrt{2\times 1065}$

$v=46.15m/s$

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Leya [2.2K]

It has a diameter of about 78 billion miles. For perspective, that's about 40% the size of our solar system, according to some estimates. And it's estimated to be about 21 billion times the mass of our sun. So there you have it, black holes can be millions of times larger than suns and planets or as small as a city.

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2 years ago

A circular conducting loop with a radius of 0.50 m and a small gap filled with a 10.0-Ω resistor is oriented in the xy-plane. If

saul85 [17]

Answer:

Current, I = 0.153 A

Explanation:

Given that,

Radius of the circular conducting loop, r = 0.5 m

Resistance of the resistor, $R=10\ \Omega$

Magnetic field, B = 1 T

Angle with z axis, $\theta=30^{\circ}$

Magnetic field increases to 10 T in 4 seconds

To find,

Magnitude of current.

Solve,

According to Faraday's law, the induced emf is given by:

$\epsilon=\dfrac{\phi_f-\phi_i}{t}$

$\phi_f\ and\ \phi_i$ are final flux and the initial flux respectively.

$\epsilon=NA\ cos\theta\dfrac{B_f-B_i}{t}$

$\epsilon=1\times \pi (0.5)^2\ cos(30)\dfrac{10-1}{4}$

$\epsilon=1.53\ V$

The magnitude of current can be calculated using the Ohm's law as :

$I=\dfrac{\epsilon}{R}$

$I=\dfrac{1.53}{10}$

I = 0.153 A

Therefore, the magnitude of the current that will be caused to flow in the loop is 0.153 A.

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4 years ago

A uniform stick has a mass of 4.42 kg and a length of 1.23 m. It is initially lying flat at rest on a frictionless horizontal su

nataly862011 [7]

10.7 rad/s is the final angular velocity of the stick.

Given:

Mass of the stick = 4.42 kg

Length of the stick = 1.23m

Force of impulse (I) = 12.8 N s

The linear velocity of the stick, $v=\frac{I}{m}$

$v=\frac{12.8 N.s (\frac{1 kg m/s^2}{1 N}) }{4.42 kg}$

$v$ $= 2.89 m/s$

Therefore, the final linear velocity of the stick is 2.89 m/s

∴ $w=\frac{12 Ir}{ml^{2} }$

$w=\frac{12 ( 12.8 N.s ) ( 46.4 cm)}{(4.42 kg) (1.23 m)^2}$

$w= \frac{12 (12.8 N.s) (46.4 cm) (\frac{10^-^2 m}{1 cm} )}{(4.42 kg) (1.23m)2}$

$w=10.7 rad/s$

Therefore, 10.7 rad/s is the final angular velocity of the stick.

Learn more about linear velocity here:

brainly.com/question/15154527

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2 years ago

A 1400kg car moving westward with a velocity of 15m/s collides with a utility pole and is brought to rest in 0.30sec. find the f

sergejj [24]

Force=(mass*velocity)-(mass*velocity)/time

force=0-(-15*1400)/0.30

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3 years ago

Read 2 more answers

A 790N person runs up a flight of 40 stairs (.25m for each step) in 20 seconds, and then down 10 steps in 5 seconds. How much to

Romashka [77]

A person runs up 40 stairs and then come down 10 steps

So total stairs upwards is given as

$N = 40 - 10 = 30$

now here we will have total height reached

$H = N\times h$

$H = 30 \times 0.25 = 7.5 m$

Now total energy used or mechanical work done is

$W = mgH$

$W = 790 \times 7.5 = 5925 J$

Now the mechanical power is given as

$P = \frac{W}{t}$

$P = \frac{5925}{20+ 5} = 237 W$

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3 years ago