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3 years ago

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For any string w = w1w2 · · · wn, the reverse of w, written w R, is the string w in reverse order, wn · · · w2w1. For any langua

ge A, let A R = {w R| w ∈ A}. Show that if A is regular, so is A R.

1 answer:

Nata [24]3 years ago

6 0

Answer:

Attached is a solution.

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A cannon fires a 0.2 kg shell with initial velocity vi = 9.2 m/s in the direction θ = 46 ◦ above the horizontal. The shell’s tra

Sedbober [7]

Answer:

∆h = 0.071 m

Explanation:

I rename angle (θ) = angle(α)

First we are going to write two important equations to solve this problem :

Vy(t) and y(t)

We start by decomposing the speed in the direction ''y''

$sin(\alpha) = \frac{Vyi}{Vi}$

$Vyi = Vi.sin(\alpha ) = 9.2 \frac{m}{s} .sin(46) = 6.62 \frac{m}{s}$

Vy in this problem will follow this equation =

$Vy(t) = Vyi -g.t$

where g is the gravity acceleration

$Vy(t) = Vyi - g.t= 6.62 \frac{m}{s} - (9.8\frac{m}{s^{2} }) .t$

This is equation (1)

For Y(t) :

$Y(t)=Yi+Vyi.t-\frac{g.t^{2} }{2}$

We suppose yi = 0

$Y(t) = Yi +Vyi.t-\frac{g.t^{2} }{2} = 6.62 \frac{m}{s} .t- 4.9\frac{m}{s^{2} } .t^{2}$

This is equation (2)

We need the time in which Vy = 0 m/s so we use (1)

$Vy (t) = 0\\0=6.62 \frac{m}{s} - 9.8 \frac{m}{s^{2} } .t\\t= 0.675 s$

So in t = 0.675 s → Vy = 0. Now we calculate the y in which this happen using (2)

$Y(0.675s) = 6.62\frac{m}{s}.(0.675s)-4.9 \frac{m}{s^{2} } .(0.675s)^{2} \\Y(0.675s) =2.236 m$

2.236 m is the maximum height from the shell (in which Vy=0 m/s)

Let's calculate now the height for t = 0.555 s

$Y(0.555s)= 6.62 \frac{m}{s} .(0.555s)-4.9\frac{m}{s^{2} } .(0.555s)^{2} \\Y(0.555s) = 2.165m$

The height asked is

∆h = 2.236 m - 2.165 m = 0.071 m

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4 years ago

I'll give you a BRAINLIEST if you help me with these questions and they have to be correct.

irina1246 [14]

2. 3 I think I’m not sure

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3 years ago

List four landforms created by wave erosion?

choli [55]

A Headland,a Sea Cave,a Sea Arch, and a sea cut cliff.

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3 years ago

A light bulb has a power rating of 60 W. What is the current running into it if it is plugged into a 120 V outlet?

kifflom [539]

Answer:

0.5 Amperes

Explanation:

Information that we have:

Power: $P=60W$

Voltage: $V=120V$

and we use the equation that relates this two quantities to the Current (I):

$I=\frac{P}{V}$

where I is the curent, P is the Power and V is the Voltage.

we substitute the values given for the Power and the Voltage to find the current:

$I=\frac{60W}{120V}\\ I=0.5A$

the Current running into the bulb is 0.5 Amperes

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8. A boy pulls a 20.0-kg box with a 140-N force at 30° above a horizontal surface. If the coefficient of kinetic friction betwee

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0.280 m is the correct answer

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