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Tresset [83]
4 years ago
15

Determine the mechanical energy of the subject: a 1 kg pendulum has a speed of 2 m/s at a height of 1 m

Physics
2 answers:
AveGali [126]4 years ago
7 0

the answer is b i believe...

Elza [17]4 years ago
4 0
D hope i helped ;) ;)
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A cyclist accelerates from rest to 8 m/s in 3 seconds. How far did the cycles travel in 3 seconds?​
GREYUIT [131]

Answer:

\boxed{\sf Distance \ travelled = 12 \ m}

Given:

Initial speed (u) = 0 m/s (Accelerates from rest)

Final speed (v) = 8 m/s

Time taken (t) = 3 seconds

To Find:

Distance travelled by cyclist (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

\boxed{ \bold{s =  (\frac{v + u}{2} )t}}

By substituting value of v, u & t in the equation we get:

\sf \implies s = ( \frac{8 + 0}{2} ) \times 3 \\  \\  \sf \implies s =  \frac{8}{2}  \times 3 \\  \\  \sf \implies s = 4 \times 3 \\  \\  \sf \implies s = 12 \: m

\therefore

Distance travelled by cyclist (s) = 12 m

4 0
3 years ago
Read 2 more answers
\nljbvjlsfhglskhg;skgh;sfjs;ojsr;ogjs;dofhs;dkhs;lifhns
vladimir1956 [14]
That is nonsense, also known as jibberish
8 0
3 years ago
What is the magnitude of velocity called?
PIT_PIT [208]
The magnitude<span> of a </span>velocity<span> vector is </span>called<span> speed. Supposethat a wind is blowing in from the direction at a speed of 50 km/h. (This meansthat the direction from which the wind blows is west of the northerly direction.) Apilot is steering a plane in the direction at an airspeed (speed in still air) of250 km/h

</span>
3 0
4 years ago
An electron enters a region with a speed of 5×10^6m/s and is slowed down at the rate of 1.25×10^-4m/s². How far does the electro
Mashutka [201]

1) The distance travelled by the electron is 1\cdot 10^{17} m

2) The time taken is 4.0\cdot 10^{10}s

Explanation:

1)

The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance travelled

For the electron in this problem,

u=5\cdot 10^6 m/s is the initial velocity

v = 0 is the final velocity (it comes to a stop)

a=-1.25\cdot 10^{-4} m/s^2 is the acceleration

Solving for s, we find the distance travelled:

s=\frac{v^2-u^2}{2a}=\frac{0-(5\cdot 10^6)^2}{2(-1.25\cdot 10^{-4})}=1\cdot 10^{17} m

2)

The total time taken for the electron in its motion can also be found by using another suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

Here we have

u=5\cdot 10^6 m/s

v = 0

a=-1.25\cdot 10^{-4} m/s^2

And solving for t, we find the time taken:

t=\frac{v-u}{a}=\frac{0-5\cdot 10^6}{-1.25\cdot 10^{-4}}=4.0\cdot 10^{10}s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

7 0
3 years ago
While hammering a nail, you put in 30 Joules of work. The hammer then puts out 10 J of
AfilCa [17]

Answer:

C    Don't worry if you thought it was D. I almost answered that.

Explanation:

Remark

You can get this just by learning the vocabulary.

Efficiency = Work Out / Work In * 100%

Work in = 30J      That's you swinging the hammer.

Work out = 10 J    That's how much of the hammer's work gets to the nail.

Efficiency = (10/30)*100

Efficiency = 1/3 * 100

Efficiency = 33%

3 0
3 years ago
Read 2 more answers
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