1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gnoma [55]
3 years ago
7

A green hoop with mass mh = 2.4 kg and radius Rh = 0.14 m hangs from a string that goes over a blue solid disk pulley with mass

md = 2.3 kg and radius Rd = 0.08 m. The other end of the string is attached to an orange block on a flat horizontal surface that slides without friction and has mass m = 3.6 kg. The system is released from rest.
(a) What is magnitude of the linear acceleration of the hoop?
(b) What is magnitude of the linear acceleration of the block?
(c) What is the magnitude of the angular acceleration of the disk pulley?
(d) What are the tensions in the string between the block and disk pulley and between the hoop and disk pulley?
(e) What is the speed of the green hoop after it falls distance d = 1.49 m from rest.
(f) Now use work-energy conservation to solve for the hoop’s speed in (e).
(g) Now instead of the block, the other end of the string is attached to a massless axel through the center of an orange sphere that rolls without slipping and has mass m = 3.6 kg and radius R = 0.22 m (Figure 2). Use energy conservation principle to solve for the speed of the hoop after it falls distance d = 1.49 m from rest.

I'm completely lost. I know that the weight of the green hoop is the only force acting on our system. Therefore: F_{net} = m_{h}g = 23.544 Newtons
For part one, I know \alpha_{n}=\frac{a}{R_{n}}. However, I'm not sure how to find \alpha_{n}.

Any help is appreciated.

Physics
1 answer:
sineoko [7]3 years ago
8 0

Answer:

a). linear acceleration of the hoop and block =  3.2895 <u>m</u>

                                                                                            s²

c). magnitude of the angular acceleration of the disk pulley = 41.119 <u>rad</u>

                                                                                                                  s²

d). tensions in the string between the block and disk pulley = 11.842 N

     tensions in the string between  the hoop and disk pulley = 15.625 N

check the pictures below for further explanation and for the remaining answers. I hope it helps you. Thank you

Explanation:

Start by writing "F=ma" equations for each of the things that moves. Also, since some of the objects (the pulley and the orange sphere) rotate, you should write "τ = Iα" equations (net torque = moment of inertia × angular acceleration) for those. In the end, you should have enough equations that you can combine them and solve for the desired quantities.

First, the hoop. There's no indication that it rotates, so we don't need a "τ = Iα" equation for it; just do "F=ma". The hoop has gravity ((mhoop)g) pulling down, and the tension in the vertical string (call it "T_v") pulling up.

Fnet = ma

You might be interested in
Mark creates a graphic organizer to review his notes about electrical force. Which labels belong in the regions marked X and Y?
sveta [45]

Answer:

The correct answer is A

Explanation:

The question requires as well the attached image, so please see that below.

Coulomb's Law.

The electrical force can be understood by remembering Coulomb's Law, that  describes the electrostatic force between two charged particles. If the particles have charges q_1 and q_2, are separated by a distance r and are at rest relative to each other, then its electrostatic force magnitude on particle 1 due particle 2 is given by:

|F|=k \cfrac{q_1 q_2}{r^2}

Thus if we decrease the distance by half we have

r_1 =\cfrac r2

So we get

|F|=k \cfrac{q_1 q_2}{r_1^2}

Replacing we get

|F|=k \cfrac{q_1 q_2}{(r/2)^2}\\|F|=k \cfrac{q_1 q_2}{r^2/4}

We can then multiply both numerator and denominator by 4 to get

|F|=k \cfrac{4q_1 q_2}{r^2}

So we have

|F|=4 \left(k \cfrac{q_1 q_2}{r^2}\right)

Thus if we decrease the distance by half we get four times the force.

Then we can replace the second condition

q_{2new} =2q_2

So we get

|F|=k \cfrac{q_1 q_{2new}}{r_1^2}

which give us

|F|=k \cfrac{q_1 2q_2}{r_1^2}\\|F|=2\left(k \cfrac{q_1 q_2}{r_1^2}\right)

Thus doubling one of the charges doubles the force.

So the answer is A.

8 0
3 years ago
Read 2 more answers
You and your dog are playing tug-of-war. For a while, neither of you are winning but after a few hard tugs, your dog pulls the t
777dan777 [17]
The dog used a greater force then me
3 0
3 years ago
A light bulb will glow when electrons flow through it. As the electron flow increases, the brightness increases as well. A stude
SIZIF [17.4K]

Answer:

Please find the answer in the explanation

Explanation:

Given that a light bulb will glow when electrons flow through it. As the electron flow increases, the brightness increases as well. A student hooks up two circuits containing three light bulbs in each circuit. In one circuit the lights are connected in series and in the other circuit the lights are hooked up in parallel.

If you could only see the lights in the circuit and the wires were covered up, how could you tell the type of circuit?

The type of the circuit can be determined if you loose or unscrew one light bulb, all other bulbs will be switched of if connected in series. But if the others remain on it is a parallel circuit.

5 0
3 years ago
A hockey puck with a mass of 0.16 kg travels at a velocity of 40 m/s toward a goalkeeper. The goalkeeper has a mass of 120 kg an
Ainat [17]

Answer:

Explanation:

Momentum is the product of mass of a body and its velocity.

Given the mass of the puck m1 = 0.16kg

velocity of the puck v1 = 40m/s

Given the mass of the goalkeeper m2 = 120kg

velocity of the goalkeeper v2= 0m/s (goal keeper at rest)

The total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper is expressed as:

m1v1 + m2v2 (their momentum will be added since they collide)

= 0.16(40) + 120(0)

= 0.16(40) + 0

= 6.4kgm/s

Let us calculate their common velocity using the conservation of momentum formula;

m1u1 + m2u2 = (m1+m2)v

6.4 = (0.16+120)v

6.4 = 120.16v

v = 6.4/120.16

v = 0.053m/s

Hence after collision, both objects move at a velocity of 0.053m/s

Momentum of the puck after collision = m1v

Momentum of the puck after collision = 0.16*0.053m/s

Momentum of the puck after collision = 0.0085kgm/s

Momentum of the keeper after collision = m2v

Momentum of the keeper after collision = 120*0.053m/s

Momentum of the keeper after collision = 6.36kgm/s

From the calculation above, it can be seen that the keeper has the greater momentum after the puck was caught since the momentum of the keeper after collision is greater than that of the puck

4 0
3 years ago
A car travels 60 km in the first 2 hours and 68 km in the next 2 hours. What’s the cars average speed?
Klio2033 [76]

Answer:

<u>The car's average speed is 32 kilometers per hour</u>

Explanation:

1. Let's review the information given to us to answer the question correctly:

First two hours = 60 kilometers

Next two hours = 68 kilometers

2. What is the car's average speed?

Total distance traveled by the car = 60 + 68

Total distance traveled by the car = 128

Total time of travel = 2 + 2 hours

Total time of travel = 4 hours

Average speed = Total distance/Total time

Replacing with the real values, we have:

Average speed = 128/4

<u>Average speed = 32 kilometers per hour</u>

4 0
4 years ago
Other questions:
  • You’ve just discovered that you are blood type O negative, highly valuable because it can be given to almost anyone in a life-th
    15·1 answer
  • An 0.80-m aluminum bar is held with its length parallel to the east-west direction and dropped from a bridge. Just before the ba
    6·1 answer
  • A long cylindrical capacitor is made of a central wire of radius a = 2.50 mm surrounded by a conducting shell of radius b = 7.50
    8·1 answer
  • A meteorologist tracks the movement of a thunderstorm with Doppler radar. At 8:00pm the storm was 55 mi northeast of her station
    11·1 answer
  • NEED ANSWER ASAP!!!
    14·1 answer
  • A bus travels north on some busy city streets for 2.5 km, and a trip
    14·1 answer
  • Which statement identifies a true relationship between the various wave components?
    8·1 answer
  • Enter an expression for the force constant for the floating raft, in terms of L, g, and the density of water, ρ.
    12·1 answer
  • The federal government spends the most on which of the following?
    7·1 answer
  • a college student rests a backpack upon his shoulder. the pack is suspended motionless by one strap from one shoulder.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!