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gizmo_the_mogwai [7]
3 years ago
12

A student is trying to calculate the density of a ball. She already knows the mass, but she needs to determine the volume as wel

l. Which of the following formulas can be used to calculate the volume of the ball?
Group of answer choices

V equals four-thirds times pi times r cubed

V equals one-third times pi times r squared times h

V = s3

V = πr2h
Chemistry
1 answer:
murzikaleks [220]3 years ago
7 0

Answer:

V equals four-thirds times pi times r cubed

Explanation:

Volume = a³ , where a is length of each side. Volume = l × w × h , where l is length, w is width and h is height. Volume = 4/3 πr³ , where r is the radius. Volume = πr²h , where r is the radius and h is the height.

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Gallium has two naturally occurring isotopes: 69ga with a mass of 68.9256 amu and a natural abundance of 60.11% and 71ga. use th
Nataly [62]

There are two naturally occurring isotopes of gallium:  mass of Ga-69 isotope is 68.9256 amu and its percentage abundance is 60.11%, let the mass of other isotope that is Ga-71 be X, the percentage abundance can be calculated as:

%Ga-71=100-60.11=39.89%

Atomic mass of an element is calculated by taking sum of atomic masses of its isotopes multiplied by their percentage abundance.

Thus, in this case:

Atomic mass= m(Ga-69)×%(Ga-69)+X×%(Ga-71)

From the periodic table, atomic mass of Ga is 69.723 amu.

Putting the values,

69.723 amu=(68.9256 amu)(\frac{60.11}{100})+X(\frac{39.89}{100})

Thus,

69.723 amu=41.4312 amu+X(\frac{39.89}{100})

Rearranging,

X=\frac{69.723 amu-41.4312 amu}{0.3989}=70.9246 amu

Therefore, mass of Ga-71 isotope is 70.9246 amu.

7 0
3 years ago
Read 2 more answers
How many unpaired electrons are in the c 2 + ​ ion?
sladkih [1.3K]
Atomic number of C is 6. Hence, there are 6 electrons in carbon.

The electronic configuration of carbon is 1s2, 2s2, 2p2

Here, there are 2 unpaired electron. However, C2+ ions have 2 electrons less as compared to C.

Hence, electronic configuration of C 2+ ion is 1s2, 2s2. All the electrons are paired in this system. So there are no unpaired electrons in C 2+ ion. 
7 0
3 years ago
Cheryl kept a potted plant near a window. After two days, she observed that the plant had drooped as shown.
Alex_Xolod [135]
A watering the plant. Plants wilt or droop when there’s not enough water because it helps reduce the amount of a surface area
3 0
3 years ago
Two different compounds are formed by the elements nitrogen and oxygen. The first compound, compound P1, contains 64.17% by mass
xz_007 [3.2K]

Answer:

Explanation:

To solve the problem, we must know the kind of compounds we are dealing with.

For the first compound, P1 and second compound P2:

                                N                       O                         N                     O

Mass percent       64.17                 35.73                  47.23               52.79

Atomic mass          14                      16                         14                    16

Number of

moles            64.17/14            35.73/16            47.23/14    52.79/16      

                            4.58                  2.23                     3.37                  3.30

Simplest

ratio                 4.58/2.23            2.23/2.23             3.37/3.30         3.3/3.3

                              2                           1                             1                        1

                             

P1 compound is N₂O

P2 compound is NO

These are the compounds,

   In N₂O = 28:16

          NO = 14:16

This is the ratio of nitrogen to a fixed mass of oxygen for the two compounds.

7 0
2 years ago
Convert the following Grams: 0.200 moles of H2S
ANEK [815]

Answer:

6.82 g H₂S

General Formulas and Concepts:

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

0.200 mol H₂S

<u>Step 2: Identify Conversions</u>

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of H₂S - 2(1.01) + 32.07 = 34.09 g/mol

<u>Step 3: Convert</u>

  1. Set up:                    \displaystyle 0.200 \ mol \ H_2S(\frac{34.09 \ g \ H_2S}{1 \ mol \ H_2S})
  2. Multiply:                  \displaystyle 6.818 \ g \ H_2S

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

6.818 g H₂S ≈ 6.82 g H₂S

7 0
3 years ago
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