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Marina86 [1]
3 years ago
13

If the boat's engine has a heat of 40,000 J, with 30,000 J exhausted into the surroundings (the heat sink), what is its efficien

cy? Show your work.
Physics
1 answer:
Yuliya22 [10]3 years ago
7 0
The answer to your quistion will be 75%

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Why does a lorry travelling at 30mph have more kinetic energy than a car travelling at the same velocity?
rjkz [21]

Answer:

Because it has more mass

Explanation:

To understand this, think about the equation of kinetic energy

KE = \frac{1}{2} m v^{2}

Kinetic energy depends on both the velocity (v) as well as the mass (m).

Because a lorry is bigger and heavier than a car, it will have more mass. With more mass, at the same velocity the lorry with have more kinetic energy.

5 0
3 years ago
Two factors that can be used to evaluate ______ are life expectancy and quality of life.
Olin [163]
Two factors that can be used to evaluate health are life expectancy and quality of life
8 0
3 years ago
Two hicers are 13 miles apart and walking toward each other. They meet in 2 hours. Find the rate of each hiker if one hiker walk
xz_007 [3.2K]

Answer:

Explanation:

Let r be the rate of the slower walker in mph

[r + (r + 1.7)](2) = 13

    (2r + 1.7)(2) = 13

         4r + 3.4 = 13

                  4r = 9.6

                    r = 2.4 mph

            r + 1.7 = 4.1 mph        

5 0
3 years ago
You are in a canyon and yell across. It takes 4 seconds for the
Naya [18.7K]

Answer:

Width = 680 [m]

Explanation:

To solve this problem we must know the speed of sound in the air, conducting an internet search, we find that this speed has a value of v = 340 [m/s].

We apply the following kinematic equation, which relates space to time, to define speed.

v = x /t

where:

x = distance [m]

t = time [s]

v = velocity [m/s]

Now replacing:

x = 340 * 4

x = 1360 [m]

But the width of the cannon is calculated when the sound wave hits the wall of the canyon, so this width is half the distance.

Width = 1360 / 2 = 680 [m]

3 0
3 years ago
Outside the space shuttle, you and a friend pull on two ropes to dock a satellite whose mass is 700 kg. The satellite is initial
MaRussiya [10]

Answer:

your friend did a work of 1717.34 J

Explanation:

The sum of the work made by your friend and you is equal the change in the kinetic energy, so:

W_a+W_b=\frac{1}{2}mv_f^{2}-\frac{1}{2}mv_i^{2}

Where W_a is the work that you did, W_b is the work that your friend did, m is the mass of the satellite and v_f and v_i are the final and initial speeds

Additionally the work that you did is equal to:

W_a=F.s

Where F and s are vectors. So, the vector s that said the displacement is calculated as:

s = <2.3, 2.6, -11.8> - <3.3, -1.6, 2.0>

s = <-1 , 4.2 , -13.8>

Therefore, W_a is:

W_a=.

W_a=(-400*-1)+(500*4.2)+(250*-13.8)\\W_a=400+2100-3450\\W_a=-950

Then, replacing the values on initial equation and solving for W_b, we get:

-950+W_b=\frac{1}{2}(700)(6.18)^{2}-\frac{1}{2}(700)(6)^{2}\\-950+W_b=767.24\\W_b=767.24+950\\W_b=1717.34J

Finally, your friend did a work of 1717.34 J

3 0
3 years ago
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