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2 years ago

How fast was the storm that hit Galveston and how men died?

Physics

1 answer:

vodomira [7]2 years ago

3 0

Answer:

The storm was a category 4 hurricane that struck Galveston, Texas, on September 8, 1900, bringing winds of 130 miles (210 km) per hour and high tides that overwhelmed the low-lying coastal city, demolishing buildings and claiming more than 8,000 lives.

00p- now I can actually answer :)

Hope that I helped you a little :0

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A 9.6 cm diameter circular loop of wire is in a 1.10 T magnetic field perpendicular to the plane of the loop. The loop is remove

Natali5045456 [20]

Answer:

Thus induced emf is 0.0531 V

Solution:

As per the question:

Diameter of the loop, $d = 9.6\ cm = 0.096\ m$

Thus the radius of the loop, R = 0.048 m

Time in which the loop is removed, t = 0.15 s

Magnetic field, B = 1.10 T

Now,

The average induced emf, e is given by Lenz Law:

$e = - \frac{\Delta \phi_{B}}{\Delta t}$

where

$\phi_{B}$ = magnetic flux = $A\Delta B$

where

A = cross sectional area

Also, we know that:

$e = - \frac{A\Delta B}{\Delta t}$

$e = - \frac{\pi r^{2}\times (0 - 1.10)}{0.15}$

$e = - \frac{\pi \times 0.048^{2}\times (0 - 1.10)}{0.15}$

e = 0.0531 V

The sketch is shown in the figure, where I indicates the direction of the induced current.

3 0

3 years ago

Read 2 more answers

The velocity at the midway point of a ball able to reach a height y when thrown with velocity vi at the origin is:

Nutka1998 [239]

Assuming the ball follows classical 2D projectile motion (moves in a parabola) and that the height y = the maximum height the ball goes in the y direction (because this would be its midpoint), then the velocity at height y is equal to the initial x component of velocity. At the midpoint, the y component is zero, so the velocity only depends on the x component. Projectiles move at constant speed in the x direction, so X = Xo. As long as you know actual values for Vi and either the initial angle or one initial component, then you can solve for Xo using trigonometry. Xo is thus the velocity of the ball once it has reached its maximum height.

7 0

3 years ago

Light enters an equilateral prism with an incident angle of 35Â° to the normal of the surface. Calculate the angle at which the

julia-pushkina [17]

Answer:

65.9°

Explanation:

When light goes through air to glass

angle of incidence, i = 35°

refractive index, n = 1.5

Let r be the angle of refraction

Use Snell's law