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KonstantinChe [14]
2 years ago
9

ether has a density of 0.736 g/cm^3 at 20 degrees C. what is the volume, in liters, of 225.0 grams of ether?

Chemistry
1 answer:
polet [3.4K]2 years ago
5 0
D = m / V

0.736 = 225.0 / V

V = 225.0 / 0.736

V = 305.7 cm³
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                     Heat is Exothermic

Explanation:

                     Specific heat capacity is the amount of heat required to raise the temperature of a given amount of substance by one degree.

Also, Exothermic reactions are those reaction in which the heat is lost from the system to surrounding while, endothermic reactions are those in which the system gains heat from the surroundings.

The equation used for this problem is as follow,

                                                 Q  =  m Cp ΔT   ----- (1)

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           Cp  =  Specific Heat Capacity  =  ??

           ΔT  =  Change in Temperature  =  70 °C  -  25 °C  =  45 °C

Solving eq. 1 for Cp,

                                Cp  =  Q / m ΔT

Putting values,

                                Cp  =  14200 J / (350 g × 45 °C)

                                Cp  =  0.901 J.g⁻¹.°C⁻¹

As the heat is lost by the metal therefore, the heat is exothermic.

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2 years ago
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4. A 14.5-L balloon is in the air where it is 20.0 C at 0.980-atm. A wind passes over and the balloon's pressure becomes 740.0-m
jeka94

The temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.

<h3>What is Combined gas law?</h3>

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

  • Initial volume V₁ = 14.5L
  • Initial pressure P₁ = 0.980atm
  • Initial temperature T₁ = 20.0°C = 293.15K
  • Final volume V₂ = 14.3L
  • Final pressure P₂ = 740.mmHg = 0.973684atm
  • Final temperature T₂ = ?

We substitute our given values into the expression above.

P₁V₁/T₁ = P₂V₂/T₂

( 0.980atm × 14.5L )/293.15K = ( 0.973684atm × 14.3L )/T₂

14.21Latm / 293.15K = 13.92368Latm / T₂

14.21Latm × T₂ = 13.92368Latm × 293.15K

14.21Latm × T₂ = 4081.72679LatmK

T₂ = 4081.72679LatmK / 14.21Latm

T₂ = 287.24K

T₂ = 14.09°C

Therefore, the temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.

Learn more about the combined gas law here: brainly.com/question/25944795

#SPJ1

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Answer:

1. Density can be used to identify a substance

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Explanation:

The calculation of the density of a substance can be used to identify the substance. If the density of a substance is calculated accurately, and compared with a table of standard densities, then we can identify that substance.

Also, density determines whether an object will float or sink in water. If an object is less dense than water then it will float in water. If it is denser than water, then it will sink in water.

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