Question

Solve this system of equations using substitution. Put your answer in ordered pair form, (x, y).3x + 2y = 2 -2x + y = 8

Answer 1

-2x + y = 8
y = 2x + 8
now sub in 2x + 8 for y in the other equation
3x + 2y = 2
3x + 2(2x + 8) = 2...distribute the 2 thru the parenthesis
3x + 4x + 16 = 2
7x = 2 - 16
7x = - 14
x = -14/7
x = -2
now sub -2 in for x in either equation to find y
-2x + y = 8
-2(-2) + y = 8
4 + y = 8
y = 8 - 4
y = 4

solution is : (-2,4)