Answer:
Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
The option is
4. 270≤Ф≤360
Step-by-step explanation:
When the terminal arm of an angle starts from the x-axis in the anticlockwise direction then the angles are always positive angles.
For Example.
Quadrant I - 0 to 90°
Quadrant II - 90° to 180°
Quadrant III - 180° to 270°
Quadrant IV - 270° to 360° ( 4. 270≤Ф≤360 )
Hence,Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
When the terminal arm of an angle starts from the x-axis in the clockwise direction than the angles are negative angles.
Quadrant IV - 0° to -90°
Quadrant III - - 90° to -180°
Quadrant II - -180° to -270°
Quadrant I - -270° to -360°
The answer is D the last one
Hey there!
Basically it wants you to add 3 and 8 from each other, what ever the answer to that part, you multiply the result by 9
Here this is what i meant
Or you could do this method too!
They both give you the result of 
So, I am assuming your expression would look like this: 
Good luck on your assignment and enjoy your day!
~
Answer:
For the function
y = cos(1/2 x)
The x-intercept can be calculated by equating the function to zero and solving for x. So,
y = cos(1/2 x) = 0
1/2 x = arc cos 0
1/2 x = 90° +180°n
x =2 (90° +180°n)
x = 180° + 360°n
or converting to radians
x = (180° + 360° n)(π/180°)
x = π + 2π n
where n is any whole number
if n = 0
x = π
Therefore, the x-intercept is π or π+2π n
Step-by-step explanation:
Plz give me brainleist worked hard thanks
