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makvit [3.9K]
3 years ago
6

A chemist makes of magnesium fluoride working solution by adding distilled water to of a stock solution of magnesium fluoride in

water. Calculate the concentration of the chemist's working solution. Round your answer to significant digits.
Chemistry
1 answer:
mojhsa [17]3 years ago
8 0

The question is incomplete, here is the complete question:

A chemist makes 600. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a stock solution of 0.00154 mol/L magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of chemist's working solution is 5.90\times 10^{-4}M

<u>Explanation:</u>

To calculate the molarity of the diluted solution (chemist's working solution), we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock magnesium fluoride solution

M_2\text{ and }V_2 are the molarity and volume of chemist's magnesium fluoride solution

We are given:

M_1=0.00154M\\V_1=230mL\\M_2=?M\\V_2=600mL

Putting values in above equation, we get:

0.00154\times 230=M_2\times 600\\\\M_2=\frac{0.00154\times 230}{600}=5.90\times 10^{-4}M

Hence, the concentration of chemist's working solution is 5.90\times 10^{-4}M

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3 years ago
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Answer:

1. three-dimensional bonding

Diamond

2. Hardest natural substance

diamond

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4. nonconductor

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4 0
3 years ago
A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g.
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Answer:

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Moles O = 0.03863 moles of oxygen

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H atoms = 4.65 *10^22 hydrogen atoms

O atoms = 2.33 *10^22 oxygen atom

Explanation:

Step 1: Data given

Mass of sucrose = 1.202 grams

Molar mass of sucrose = 342.3 g/mol

Step 2: Calculate moles of sucrose

Moles sucrose = Mass sucrose / molar mass sucrose

Moles sucrose = 1.202 grams / 342.3 g/mol

Moles sucrose = 0.003512 moles

Step 3: Calculate moles of each element

For 1 mol of C12H22O11 we have 12 moles of carbon, 22 moles of hydrogen and 11 moles of oxygen

Moles C: 12*0.003512 = 0.04214 moles carbon

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Step 4: Calculate the number of atoms

C atoms = 6.022 *10^23 / mol * 0.04214 moles = 2.54 *10^22 atoms carbon

H atoms = 6.022 * 10^23 / mol * 0.07726 moles = 4.65 *10^22 atoms H

O atoms = 6.022 * 10^23 / mol * 0.03863 moles = 2.33 *10^22 atoms O

0.003512 moles of sucrose containse 6.022 *10^23 * 0.003512 = 2.11 * 10^21 sucrose molecules

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Answer:

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There are two naturally occurring isotopes of boron. 10 B has a mass of 10.0129 u. 11 B has a mass of 11.0093 u. Determine the a
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<h2>Natural Abundance for 10B is 19.60%</h2>

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