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Alik [6]
3 years ago
6

Which is a homogeneous mixture? A air B pizza C jar of mixed nuts D salad dressing

Physics
1 answer:
rusak2 [61]3 years ago
5 0

Answer:

A) Air

Explanation:

A homogenous mixture is one that has uniform composition throughout. Air is comprised of several types of molecules (oxygen, carbon, nitrogen...). If you take a chunk of air, you will get the same ratio of those molecules if you take a different chunk of it. They will be made of the exact same things no matter where you take your sample.

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A steel ball with mass m is suspended from the ceiling at the bottom end of a light, 17.0-m-long rope. The ball swings back and
iogann1982 [59]

Answer:

1. 18.25 m/s

2. 0 m/s

Explanation:

1.So the centripetal acceleration of the ball at this lowest point must be, taking gravity into account

a_c = \frac{T - mg}{m} = \frac{3mg - mg}{m} = 2g

The speed at this point would then be

v^2 = a_c r = 2gr = 2*9.8*17 = 333.2

v = \sqrt{333.2} = 18.25 m/s

2. Similarly, if T = mg, then the centripetal acceleration must be

a_c = \frac{T - mg}{m} = \frac{mg - mg}{m} = 0

As the ball has no centripetal acceleration, its speed must also be 0 as well.

6 0
4 years ago
It is difficult to lift a Large stone but easy to lift a smaller one on the surface of the earth .why ​?
denis23 [38]

Answer:

the weight of the large stone is greater than a small one

Explanation:

because the large stone has greater mass then the small stone.therefore it is difficult to lift the large stone on the surface of the earth but easy to lift the small one

8 0
3 years ago
Suppose that a spiral galaxy is located at the center of a spherically symmetric dark matter halo
Novosadov [1.4K]

To solve the problem it is necessary to use the concepts of Orbital Speed considering its density, and its angular displacement.

In general terms the Orbital speed is described as,

V_{orbit} = \sqrt{\frac{G\rho 4\pi r^3}{3}}

PART A) If the orbital speed of a star in this galaxy is constant at any radius, then,

\frac{4\pi G\rho r}{3} = \frac{v^2}{r}

\frac{4\pi G\rho r}{1} = \frac{3v^2}{r}

\frac{\rho}{1} = \frac{3v^2}{r^2 4\pi G}

\rho = \frac{1}{r^2}

PART B) This time we havev=\omega t, where \omega is the angular velocity (constant at this case)

\frac{4\pi G\rho r}{3} = \frac{v^2}{r}

\frac{4\pi G\rho r}{3} = \frac{(\omega r)^2}{r}

\rho = \frac{3\omega r}{4\pi Gr}

\rho = \frac{3\omega^2}{4\pi G} \propto constant

PART C) If the total mass interior to any radius r is a constant,

\frac{4\pi G\rho r}{3} = \frac{v^2}{r}

\frac{GM}{r^2}=\frac{v^2}{r}

v = \sqrt{\frac{GM}{r}}

v= \sqrt{\frac{1}{r}}

3 0
4 years ago
Formulating an Investigative Question
valentina_108 [34]

Answer:

How do mass and speed affect kinetic energy?

Explanation:

This was edges sample resopnse so do not copy and just put this in your own words.

Have a great day whoever reads this.

8 0
3 years ago
A piano string having a mass per unit length equal to 5.20 10-3 kg/m is under a tension of 1 450 N. Find the speed with which a
DedPeter [7]

Answer:

The wave in the string travels with a speed of 528.1 m/s

Explanation:

Wave speed of sound waves in a string, v, is related to the Tension in the string, T, and the mass per unit length, μ, by the relation,

v = √(T/μ)

μ = 5.20 × 10⁻³ kg/m

T = 1450N

v = √(1450/0.0052) = 528.1 m/s

Hope this Helps!!!

6 0
3 years ago
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