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3 years ago

Newton’s third law of motion says that for every action there is a(n) and opposite reaction

Physics

2 answers:

lyudmila [28]3 years ago

7 0

Answer:

Newton's third law of motion says that for every action there is an equal and opposite reaction.

Explanation:

This law explains that when two bodies interact with one another, two forces facilitates this process.These forces are opposite is action but equal in magnitude.For example, when sitting on a coach, the body exerts force on the coach downwards and the coach exerts an upward force on the body.These two forces are the action and reaction forces.

katrin2010 [14]3 years ago

6 0

Answer:

Explanation:

Newton's third law of motion says that for every action there is equal magnitude force acting in opposite direction. For example if we push a wall with our hands, the wall will also exert the force of equal magnitude in opposite direction.This is general thing when two bodies interacts with each other they produce same force in opposite direction on each other.

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Travels 11,000 feet along a dark desert highway if the car averages 84 mph find the amount of time to cover this distance

laila [671]

The time taken by traveler to cover the distance is,

$t=\frac{d}{v}$

Substitute the known values,

$\begin{gathered} t=\frac{(11000\text{ ft)}}{(84\text{ mph)(}\frac{1.46667\text{ ft/s}}{1\text{ mph}})_{}} \\ \approx89.3\text{ s} \end{gathered}$

Therefore, the time taken by traveler to cover the distance is 89.3 s.

5 0

1 year ago

A space station shaped like a giant wheel has a radius of a radius of 153 m and a moment of inertia of 4.16 × 10⁸ kg·m² (when it

Naya [18.7K]

Answer:

a = 1.709g

Explanation:

Given the absence of external forces being applied in the space station, it is possibly to use the Principle of Angular Momentum Conservation, which states that:

$I_{o} \cdot \omega_{o} = I_{f} \cdot \omega_{f}$

The required initial angular speed is obtained herein:

$g= \omega_{o}^{2}\cdot R_{ss}$

$\omega_{o}=\sqrt{\frac{g}{R_{ss}} }$

$\omega_{o}= \sqrt{\frac{9.807\,\frac{m}{s^{2}} }{153\,m} }$

$\omega_{o} \approx 0.253\,\frac{rad}{s}$

The initial moment of inertia is:

$I_{o} =I_{ss}+n\cdot m_{person}\cdot R_{ss}^{2}$

$I_{o} = 4.16\times 10^{8}\,kg\cdot m^{2}+(150)\cdot (65\,kg)\cdot (153\,m)^{2}$

$I_{o} = 6.442\times 10^{8}\,kg\cdot m^{2}$

The final moment of inertia is:

$I_{f} =I_{ss}+n\cdot m_{person}\cdot R_{ss}^{2}$

$I_{f} = 4.16\times 10^{8}\,kg\cdot m^{2}+(50)\cdot (65\,kg)\cdot (153\,m)^{2}$

$I_{f} = 4.921\times 10^{8}\,kg\cdot m^{2}$

Now, the final angular speed is obtained:

$\omega_{f} = \frac{I_{o}}{I_{f}}\cdot \omega_{o}$

$\omega_{f} = \frac{6.442\times 10^{8}\,{kg\cdot m^{2}}}{4.921\times 10^{8}\,kg\cdot m^{2}} \cdot (0.253\,\frac{rad}{s} )$

$\omega_{f} = 0.331\,\frac{rad}{s^}$

The apparent acceleration is:

$a_{f} = \omega_{f}^{2}\cdot R_{ss}$

$a_{f} = (0.331\,\frac{rad}{s} )^{2}\cdot (153\,m)$

$a_{f} = 16.763\,\frac{m}{s^{2}}$

This is approximately 1.709g.

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4 years ago

Use the periodic table and your knowledge of isotopes to complete these statements.

klasskru [66]

Use the periodic table and your knowledge of isotopes to complete these statements.

When polonium-210 emits an alpha particle, the child isotope has an atomic mass of ⇒ 206.

I-131 undergoes beta-minus decay. The chemical symbol for the new element is ⇒ Xe.

Fluorine-18 undergoes beta-plus decay. The child isotope has an atomic mass of ⇒ 18.

7 0

3 years ago

Read 2 more answers

Calculate the velocity of a wave that has a frequency of 60 Hz and wavelength of 2.0 m/s

mote1985 [20]

Answer:We have , a relation in frequency f and wavelength λ of a wave having the velocity v as ,

v=fλ ,

given f=60Hz , λ=20m ,

therefore velocity of wave , v=60×20=1200m/s

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3 years ago

Describe the electron's path in this field. Describe the electron's path in this field. The electron will move in a clockwise ci

Jlenok [28]

Answer: D - The electron will move in a counterclockwise circular path if viewed in the direction of the magnetic field.

Explanation:

When the electron enters the field at an angle to the field direction the resulting path of the electron will be helical. Such motion occurs above the poles of the Earth where charges particles from the Sun spiral through the Earth's field to produce the aurorae.

Magnetic force on an electron = BILsinØ = B[e/t][vt] = BevØ

where v is the electron velocity

In a magnetic field the force is always at right angles to the motion of the electron (Fleming's left hand rule) and so the resulting path of the electron is circular.

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3 years ago

Newton’s third law of motion says that for every action there is a(n) and opposite reaction​

Newton’s third law of motion says that for every action there is a(n) and opposite reaction