<span>Let equation A be
h=ut+<span>12</span>g<span>t2 </span></span>
for 1st stone:
<span>h=<span>12</span> g<span>t2
</span></span>eq.-(A)
for 2nd stone:
<span>h=32m/s(t−1.6s)+<span>12</span>g(t−1.6s<span>)2
</span></span><span>h=32m/s∗t−51.5m+<span>12</span>g<span>t2</span>+12.544m−15.68m/s∗t
</span>
<span>h=16.32m/s∗t+h−38.656m
</span>
<span>t=2.3686s
</span>
now putting the value of t in eqn. A
<span><span>h=27.49m</span></span>
Answer:
V4=9.197v
Explanation:
Given:
V1= 18v ,V2= 12v ,r1=r5=58ohms ,r2=r6=124ohms , r3=47ohms ,r4= 125ohms
V4= I4R4 = V2/(R4 + R5)×R4
V4= 12×125 /(125 + 58)
V4=1500/183 =9.197v
Work is done when a spring is extended or compressed . Elastic potential energy is stored in the spring hope that helpss.
