Answer:
Explanation:
Magnus is installing a re
Answer
given,
mass of the steel ball = 35 g = 0.035 kg
the horizontal distance is
( v cos θ ) t = 4.8..........(1)
the vertical distance is
...(2)
since,
..................(3)
using equation(2) and (3)
(v t)² (cos²θ+ sin²θ) = 4.8² + 4²
(v t)² = 39.04
t = 0.76 s
the speed is
vt = 6.25
v × 0.76 = 6.25
v = 8.22 m/s
Answer:
The difference of power is
ΔP = 172.767 kPa
Explanation:
ρ = 1390 kg / m³
v = 9.63 m/s
d₁ = 10.1 cm , d₂ = 15.3 cm
Δz = 8.85 m
To find the difference ΔP between the fluid pressure at locations 2 and the fluid pressure at location 1
ΔP = ρ * g * Z + ¹/₂ * ρ * v² * ( 1 - (d₁ / d₂)⁴ )
ΔP = 1390 kg / m³ * 9.8 m/s² * 8.85 m + 0.5 * 1390 kg / m³ *(9.63 m /s)² * (1 - (0.101 m / 0.153 m )⁴ )
ΔP = 172.767 x 10 ³ Pa
ΔP = 172.767 kPa