Question

A Hollywood stuntman is preparing for a dangerous car stunt. He must drive a car at high speed toward the edge of a cliff and break just before going over the edge. The distance from the car’s starting position to the edge is 100 m. The car’s breaks can manage a maximum deceleration of -8 m/s^2. If the whole movie sequence is going to take 10 seconds, what is the maximum starting velocity that the car can possess if the stuntman is to be successful?

Answer 1

Answer:

 Maximum starting velocity that the car can possess if the stuntman is to be successful = 50 m/s

Explanation:

  We have equation of motion , $s= ut+\frac{1}{2} at^2$, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

 In this case, displacement = 100 meter, acceleration = -8 $m/s^2$, time = 10 seconds, we need to find initial velocity.

Substituting

  $100= u*10-\frac{1}{2} *8*10^2\\ \\ u*10=100+400\\ \\ 10u=500\\ \\ u=50m/s$

So, Maximum starting velocity that the car can possess if the stuntman is to be successful = 50 m/s