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LenKa [72]
3 years ago
11

A vw bug is driving north on a straight two lane road at a constant 54 mph and chevy impala south at 47 on the same road (but di

fferent lane). What is the velocity of the chevy impala relative to the vw bug?
A.101 mph, north
B.7mph, south
C. 101mph, south
D.7mph, north
Physics
1 answer:
mario62 [17]3 years ago
5 0

Velocity of vw bug is given as

v_1 = 54 mpH towards north

velocity of imphala is given as

v_2 = 47 mph towards south

now we need to find velocity of imphala relative to bug

v_{21} = v_2 - v_1

v_{21} = 47 - (-54) = 101 mpH

so the speed is 101 mpH towards south so correct option is C

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Which rational number could be graphed between 0 and 1?A number line going from negative 5 to positive 3 in increments of 1.Nega
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In order to find which rational number is between 0 and 1, let's convert them into their decimal form:

\begin{gathered} \text{negative one-half:} \\ -\frac{1}{2}=-0.5 \\  \\ \text{one}-\text{fourth:} \\ \frac{1}{4}=0.25 \\  \\ \text{three}-\text{halves:} \\ 3\cdot\frac{1}{2}=\frac{3}{2}=1.5 \\  \\ 1.75 \end{gathered}

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7 0
1 year ago
An object falls from rest on a high tower and takes 5.0 s to hit the ground. Calculate the object's position from the top of the
Lena [83]

Answer:

After 1 sec = 4.9 m

After 2 sec = 19.6 m

After 3 sec = 44.1 m

After 4 sec =  78.4 m

After 5 sec = 122.5 m

Explanation:

After 1 sec:

<em>u=0m/s   t=1 s  a=9.8m/s²</em>

s = ut + (1/2)at²

=0(1) + (1/2)(9.8)(1²) = 4.9m

After 2 sec:

<em>u=0m/s   t=2 s  a=9.8m/s²</em>

s = ut + (1/2)at²

=0(2) + (1/2)(9.8)(2²) = 19.6m

After 3 sec:

<em>u=0m/s   t=3 s  a=9.8m/s²</em>

s = ut + (1/2)at²

=0(3) + (1/2)(9.8)(3²) = 44.1m

After 4 sec:

<em>u=0m/s   t=4 s  a=9.8m/s²</em>

s = ut + (1/2)at²

=0(4) + (1/2)(9.8)(4²) = 78.4m

After 5 sec:

<em>u=0m/s   t=5 s  a=9.8m/s²</em>

s = ut + (1/2)at²

=0(5) + (1/2)(9.8)(5²) = 122.5m

7 0
2 years ago
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