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LenKa [72]
3 years ago
11

A vw bug is driving north on a straight two lane road at a constant 54 mph and chevy impala south at 47 on the same road (but di

fferent lane). What is the velocity of the chevy impala relative to the vw bug?
A.101 mph, north
B.7mph, south
C. 101mph, south
D.7mph, north
Physics
1 answer:
mario62 [17]3 years ago
5 0

Velocity of vw bug is given as

v_1 = 54 mpH towards north

velocity of imphala is given as

v_2 = 47 mph towards south

now we need to find velocity of imphala relative to bug

v_{21} = v_2 - v_1

v_{21} = 47 - (-54) = 101 mpH

so the speed is 101 mpH towards south so correct option is C

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Answer:

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A free flow body diagram illustrating what the question represents is attached in the file below;

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N_A+N_B = 441    ------- equation (1)

Considering the forces on the horizontal axis:

\sum f_x = 0

F_A +F_B  = P

where ;

\mathbf{ F_A \ and \ F_B } are the static friction at center point A and B respectively.

which can be written also as:

\mu_s N_A + \mu_s N_B  = P

\mu_s( N_A +  N_B)  = P

replacing our value from equation (1)

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b) Since the horizontal distance between the casters A and B is 480 mm; Then half the distance = 480 mm/2 = 240 mm = 0.24 cm

the largest value of "h" allowed for  the cabinet is not to tip over is calculated by determining the limiting condition  of the unbalanced torque whose effect is canceled by the normal reaction at N_A and it is shifted to N_B:  

Then:

\sum M _B = 0

P*h = mg*0.24

h =\frac{45*9.8*0.24}{132.3}

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Thus; the largest value of "h" allowed if the cabinet is not to tip over is 0.8 m

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