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Alex787 [66]
3 years ago
14

On his fishing trip Justin takes the boat 25 km south. The fish aren’t biting so he goes 10 km west. He follows a school of fish

15 km north. What distance did he cover? What was his displacement?
Physics
1 answer:
vodomira [7]3 years ago
3 0

Distance is 50 km

Displacement is 10 km

<u>Explanation:</u>

Given:

Distance toward south, x = 25 km

Distance towards west, y = 10 km

Distance towards north, z = 15 km

(a) Total distance, D = ?

Total distance, D = x + y + z

                       D = 25 + 10 + 15

                       D = 50km

(b) Displacement, d = ?

Displacement = final position - initial position

                      = 10 - 0 km

                      = 10km

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A tree loses water to the air by the process of transpiration at the rate of 110 g/h. This water is replaced by the upward flow
Ksivusya [100]

Answer:

The answer is 1.87nm/s.

Explanation:

The 110g/hr  water loss must be replaced by 110g/hr of sap. 110g of sap corresponds to a volume of  

110g \div \dfrac{1040*10^3g}{1*10^6cm^3}  = 106cm^3

thus rate of sap replacement is

106cm^3/hr = 106*10^{-6}m^3/3600s  = 2.94*10^{-8}m^3/s

The volume of sap in the vessel of length x is

V = Ax,

where A is the cross sectional area of the vessel.

For 2000 such vessels, the volume is

V = 2000Ax

taking the derivative of both sides we get:

\dfrac{dV}{dt} = 2000A \dfrac{dx}{dt}

on the left-hand-side \dfrac{dx}{dt} is the velocity v of the sap, and on right-hand-side \dfrac{dV}{dt}  = 2.94*10^{-8}m^3/s; therefore,

2.94*10^{-8}m^3/s=2000Av

and since the cross-sectional area is

A = \pi (\dfrac{100*10^{-3}m}{2} )^2 = 7.85*10^{-3}m^2;

therefore,

2.94*10^{-8}m^3/s =2000(7.85*10^{-3}m^2)v

solving for v we get:

v = \dfrac{2.94*10^{-8}m^3/s}{2000(7.85*10^{-3}m^2)}

\boxed{v =1.875*10^{-9}m/s = 1.875nm/s}

which is the upward speed of the sap in each vessel.

8 0
3 years ago
U235 + n → Xe134 + Sr100 + 2n
xenn [34]
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Note in the fission equation, that out come two neutrons. They go off and produce a similar fission in another U235 nucleus into a chain reaction which, i not moderated by, say, Boron, can end up as a "mushroom cloud".
8 0
2 years ago
A scientist that applies the laws of science to the needs of communities is called _____.
s2008m [1.1K]

Answer:

The experimental scientist

5 0
2 years ago
What is the kinetic energy of a an 80kg football player running at 8 m/s?
Ugo [173]
In the question it is already given that the football player is 80 kg.
Then the mass of the football player = 80 kg
Velocity at which the football player is running = 8 m/s
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Now we have to put the known data in this equation to find the actual velocity of the footballer.
</span> <span></span>So
Kinetic Energy of the footballer = 0.5 * 80 * (8 * 8)
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4 0
3 years ago
Two airplanes leave an airport at the same time.The velocity of the first airplane is 700 m/h at a heading of 31.3 the velocity
MArishka [77]

Here in order to find out the distance between two planes after 3 hours can be calculated by the concept of relative velocity

v_{12} = v_1 - v_2

here

speed of first plane is 700 mi/h at 31.3 degree

v_1 = 700 cos31.3\hat i + 700 sin31.3\hat j

v_1 = 598.12\hat i + 363.7\hat j

speed of second plane is 570 mi/h at 134 degree

v_2 = 570 cos134 \hat i + 570 sin134 \hat j

v_2 = -396\hat i + 410\hat j

now the relative velocity is given as

v_{12} = (598.12 + 396)\hat i + (363.7 - 410)\hat j

v_{12} =994.12\hat i -46.3 \hat j

now the distance between them is given as

d = v* t

d = (994.12 \hat i - 46.3 \hat j)* 3

d = 2982.36\hat i - 138.9\hat j

so the magnitude of the distance is given as

d = \sqrt{2982.36^2 + 138.9^2}

d = 2985.6 miles

so the distance between them is 2985.6 miles

5 0
3 years ago
Read 2 more answers
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