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Cloud [144]
3 years ago
10

An object on earth with a mass of 7.5 kg has a weight of

Physics
1 answer:
kumpel [21]3 years ago
6 0

Answer:

75kgms/2

Explanation:

weight=mass*g=7.5kg*10ms/1=75

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Compare the gravity between these pairs, each consisting of an Earth-like planet and its star. You are given the mass of the pla
Maru [420]

Answer:

The answer is below

Explanation:

Newton's law of gravity states that the force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. The law is expressed by the formula:

F=G\frac{m_1m_2}{r^2} \\\\Where\ F=force,G=gravitational\ constant, m_1\ and\ m_1=mass\ of\ objects,r\ =distance\ between \ the\ two\ objects.

The masses and distances for this question is in common units, Therefore the result would be in ratios

a) 4 MEarth / 2 MSolar / 3 AU

The force (F) = (4 * 3) / 3² = 4/3

b) 1 MEarth / 1 MSolar / 1 AU

The force (F) = (1 * 1) / 1² = 1

c) 1 MEarth / 2 MSolar / 2 AU

The force (F) = (1 * 2) / 2² = 1/2

6 0
2 years ago
Baseball player swings and hits a pop fly straight up in the air to the catcher. the height of the baseball in meters t seconds
andre [41]
The height at time t is given by
h(t) = -4.91t² + 34.3t + 1

When the ball reaches maximum height, its derivative, h'(t) = 0.
That is,
-2(4.91)t+34.3 = 0
-9.82t + 34.3 = 0
t = 3.4929 s

Note that h''(t) = -9.82 (negative) which confirms that h will be maximum.

The maximum height is
hmax = -4.91(3.4929)² + 34.3(3.4929) + 1
          = 60.903 m

Answer:
The ball attains maximum height in 3.5 s (nearest tenth).
The ball attains a maximum height of 60.9 m (nearest tenth)

4 0
3 years ago
Two electrons are passing 20.0 mm apart. What is the electric repulsive force that they exert on each other
vladimir1956 [14]
15.0 I’m pretty sure that’s the answer to your question
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2 years ago
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Find the frequency of a wave with a period of 0.5 seconds
strojnjashka [21]

Frequency of the wave is 2 per second

Explanation:

  • Frequency is the number of times waves pass at a particular point of time. Here, time period = 0.5 s
  • Frequency is given by the formula

f = 1/T, where f is the frequency and T is the time period

⇒ f = 1/0.5 = 2 per second

8 0
3 years ago
Interactions of current carrying wires
koban [17]
Physics stack exchange
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2 years ago
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